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There are 13 terms in an evenly spaced set.

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There are 13 terms in an evenly spaced set. [#permalink]

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New post 13 Aug 2017, 23:23
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There are 13 terms in an evenly spaced set. What is the sum of all the terms?

(1) 7th term of the set is 47.

(2) 1st term of the set is 5.


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[Reveal] Spoiler: OA

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Re: There are 13 terms in an evenly spaced set. [#permalink]

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New post 13 Aug 2017, 23:55
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If the set is evenly spaced, the terms in this set are in an AP.
The mean = median for such evenly spaces sets.

Since, there are 13 terms in the set, the mean = median = 7th term

1. 7th term of the set is 47.
The sum is 13 * 7th element. (Sufficient)

2. 1st term of the set is 5.
Without knowing the common difference of the terms
it is not possible to find out the sum of the terms.
If the common difference is 2, the numbers are 5,7,9,11....
where as if the common difference is 3, the numbers are 5,8,11,14....
So, we cannot arrive at a constant mean or median,
because of which we cannot clearly give the sum of the terms of the set.(Insufficient)(Option A)
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Kudos [?]: 592 [1], given: 16

Re: There are 13 terms in an evenly spaced set.   [#permalink] 13 Aug 2017, 23:55
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