Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Have you ever wondered how to score a PERFECT 805 on the GMAT? Meet Julia, a banking professional who used the Target Test Prep course to achieve this incredible feat. Julia's story is nothing short of an inspiration.
Think a 100% GMAT Verbal score is out of your reach? Target Test Prep will make you think again! Our course uses techniques such as topical study and spaced repetition to maximize knowledge retention and make studying simple and fun.
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
If the set is evenly spaced, the terms in this set are in an AP. The mean = median for such evenly spaces sets.
Since, there are 13 terms in the set, the mean = median = 7th term
1. 7th term of the set is 47. The sum is 13 * 7th element. (Sufficient)
2. 1st term of the set is 5. Without knowing the common difference of the terms it is not possible to find out the sum of the terms. If the common difference is 2, the numbers are 5,7,9,11.... where as if the common difference is 3, the numbers are 5,8,11,14.... So, we cannot arrive at a constant mean or median, because of which we cannot clearly give the sum of the terms of the set.(Insufficient)(Option A)
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.