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11 Mar 2020, 03:21
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D
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Difficulty:
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Question Stats:
76% (01:18) correct
24%
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There are enough available spaces on a school team to select at most 1/3 of the 50 students trying out for the team. What is the greatest number of students that could be rejected while still filling all available spaces for the team?
(A) 16
(B) 17
(C) 33
(D) 34
(E) 35
(A) 16
(B) 17
(C) 33
(D) 34
(E) 35
11 Mar 2020, 06:27
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Bunuel
There are enough available spaces on a school team to select at most 1/3 of the 50 students trying out for the team. What is the greatest number of students that could be rejected while still filling all available spaces for the team?
(A) 16
(B) 17
(C) 33
(D) 34
(E) 35
(A) 16
(B) 17
(C) 33
(D) 34
(E) 35
1/3 of 50 = (1/3)(50) = 50/3 = 16 2/3
Since the number of available spaces cannot be greater than 16 2/3, there must be 16 available spaces.
So, 16 students (among the original 50 students) can be selected to join the team, which means the other 34 students must be rejected.
Answer: D
Cheers,
Brent
11 Mar 2020, 08:31
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Bunuel
There are enough available spaces on a school team to select at most 1/3 of the 50 students trying out for the team. What is the greatest number of students that could be rejected while still filling all available spaces for the team?
(A) 16
(B) 17
(C) 33
(D) 34
(E) 35
(A) 16
(B) 17
(C) 33
(D) 34
(E) 35
number selected or rejected has to be an integer so factor <50 is 48 ; 1/3*48 ; 16 so rejected would be
50-16 ; 34
IMO B
