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06 Dec 2015, 09:38
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
61% (02:50) correct
39%
(02:52)
wrong
based on 433
sessions
History
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Time
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Not Attempted Yet
Math Revolution and GMAT Club Contest Starts!
QUESTION #8:
There is a sequence \(A_n\) such that \(A_1=2\), \(A_2=5\), and \(A_n=\frac{A_{n-1}}{A_{n-2}}\),when n is an integer greater than 2. What is the value of \(A_{149}\)?
A. 2
B. 5
C. 2.5
D. 1/2
E. 1/5
Check conditions below:
Math Revolution and GMAT Club Contest
The Contest Starts November 28th in Quant Forum
We are happy to announce a Math Revolution and GMAT Club Contest
For the following four (!) weekends we'll be publishing 4 FRESH math questions per weekend (2 on Saturday and 2 on Sunday).
To participate, you will have to reply with your best answer/solution to the new questions that will be posted on Saturday and Sunday at 9 AM Pacific.
Then a week later, the forum moderator will be selecting 2 winners who provided most correct answers to the questions, along with best solutions. Those winners will get 6-months access to GMAT Club Tests.
PLUS! Based on the answers and solutions for all the questions published during the project ONE user will be awarded with ONE Grand prize:
PS + DS course with 502 videos that is worth $299!
All announcements and winnings are final and no whining
GMAT Club reserves the rights to modify the terms of this offer at any time.NOTE: Test Prep Experts and Tutors are asked not to participate. We would like to have the members maximize their learning and problem solving process.
Thank you!
06 Dec 2015, 11:43
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this is a "spot the pattern" question type.
nothing difficult.
a3 = 2.5
a4=0.5
a5=0.2
a6=0.4
a7=2
a8=5
a9=2.5
a10=0.5
a11=0.2
a12=0.4
a13=2
a14=5
we can see that every the pattern repeats every 6th term. ex. 1+6 = 7. 7+6=13. so term a1, a7, a13, etc. will be 1/5.
now, we can deduct that term a149 will be 2.
nothing difficult.
a3 = 2.5
a4=0.5
a5=0.2
a6=0.4
a7=2
a8=5
a9=2.5
a10=0.5
a11=0.2
a12=0.4
a13=2
a14=5
we can see that every the pattern repeats every 6th term. ex. 1+6 = 7. 7+6=13. so term a1, a7, a13, etc. will be 1/5.
now, we can deduct that term a149 will be 2.
06 Dec 2015, 14:32
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We have a series defined in the question, and we are asked for the 149th term in the series.
The first thing to check is whether the series repeats. It could be expected due to the fact that the nth term depends on a division of the previous two terms, and also we know that this can often be the case in the GMAT when asked for a term much later in the series.
The series goes:
\(2\), \(5\), \(5/2\), \(1/2\), \(1/5\), \(2/5\), \(2\), \(5\)
We can see that the series has repeated, and will therefore loop forever, with 6 unique locations.
If we divide 149 by 6, the remainder will tell us which term in the series is the 149th term. 149 divided by 6 gives us the remainder 5, therefore the fifth term, \(1/5\) will also be the 149th term. Therefore the answer is E.
The first thing to check is whether the series repeats. It could be expected due to the fact that the nth term depends on a division of the previous two terms, and also we know that this can often be the case in the GMAT when asked for a term much later in the series.
The series goes:
\(2\), \(5\), \(5/2\), \(1/2\), \(1/5\), \(2/5\), \(2\), \(5\)
We can see that the series has repeated, and will therefore loop forever, with 6 unique locations.
If we divide 149 by 6, the remainder will tell us which term in the series is the 149th term. 149 divided by 6 gives us the remainder 5, therefore the fifth term, \(1/5\) will also be the 149th term. Therefore the answer is E.
GMAT Club reserves the rights to modify the terms of this offer at any time.
