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08 Feb 2004, 14:38
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This should be fairly easy
If x=12 what is the range of set { 5,8,x,y }
1) 3x+ 5y = 72
2) -7x+7y = 56
If x=12 what is the range of set { 5,8,x,y }
1) 3x+ 5y = 72
2) -7x+7y = 56
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08 Feb 2004, 15:00
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is it C as for statement (1) i am getting x=4 and y=12 and x= -6 and y=18 and for statement (2) x= 4 and y= 12. So by combining both we get x=4 and y=12.
08 Feb 2004, 23:45
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I think the answer is B. I solved this problem via the graphical analysis which shows that Statement I gives a host of values of (x,y) satisfying the given conditions and hence the answer is not unique.
Statement II gives only one value of (x,y)=(4,12) which satisfies all the conditions ie. x <=4,y>=12 and -7x+7y=56. Hence the range of the given set of nos. is unique ie. (12-4)=8.
Anand, please confirm.
Statement II gives only one value of (x,y)=(4,12) which satisfies all the conditions ie. x <=4,y>=12 and -7x+7y=56. Hence the range of the given set of nos. is unique ie. (12-4)=8.
Anand, please confirm.
