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Updated on: 24 Sep 2014, 05:47
Originally posted by KunalPratap on 11 Aug 2011, 08:40.
Last edited by Bunuel on 24 Sep 2014, 05:47, edited 3 times in total.
Last edited by Bunuel on 24 Sep 2014, 05:47, edited 3 times in total.
Renamed the topic, edited the question and added the OA.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
56% (02:48) correct
44%
(02:58)
wrong
based on 294
sessions
History
Date
Time
Result
Not Attempted Yet
Tom, working alone, can paint a room in 6 hours. Peter and John, working independently, can paint the same room in 3 hours and 2 hours, respectively. Tom starts painting the room and works on his own for one hour. He is then joined by Peter and they work together for an hour. Finally, John joins them and the three of them work together to finish the room, each one working at his respective rate. What fraction of the whole job was done by Peter?
A. 1/9
B. 1/6
C. 1/3
D. 7/18
E. 4/9
OPEN DISCUSSION OF THIS QUESTION IS HERE: tom-working-alone-can-paint-a-room-in-6-hours-peter-and-126629.html
A. 1/9
B. 1/6
C. 1/3
D. 7/18
E. 4/9
OPEN DISCUSSION OF THIS QUESTION IS HERE: tom-working-alone-can-paint-a-room-in-6-hours-peter-and-126629.html
17 Aug 2014, 03:53
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fluke
KunalPratap
T can work laone and finishes job in 6 hours, P & J can do the same independently in 3 and 2 hours each. P starts working and after 1 hour P joins, both of them work for another 1 hour. After that J joins them and thet finish the job together. What was freaction of job done by P????
1) 1/9
2) 1/6
3) 1/3
4) 7/18
5) 4/9
1) 1/9
2) 1/6
3) 1/3
4) 7/18
5) 4/9
Please correct your question. Who starts and who joins?
The proper version of this question is below:
Tom, working alone, can paint a room in 6 hours. Peter and John, working independently, can paint the same room in 3 hours and 2 hours, respectively. Tom starts painting the room and works on his own for one hour. He is then joined by Peter and they work together for an hour. Finally, John joins them and the three of them work together to finish the room, each one working at his respective rate. What fraction of the whole job was done by Peter?
A. 1/9
B. 1/6
C. 1/3
D. 7/18
E. 4/9
Let the time when all three were working together be t hours. Then:
Tom worked for t+2 hour and has done 1/6*(t+2) part of the job;
Peter worked for t+1 hour and has done 1/3*(t+1) part of the job;
John worked for t hours and has done 1/2*t part of the job:
1/6*(t+2)+1/3*(t+1)+1/2*t=1 --> multiply by 6 --> (t+2)+(2t+2)+3t=6 --> t=1/3;
Hence Peter has done 1/3*(1/3+1)=4/9 part of the job.
Answer: E.
[color=#ff0000]OPEN DISCUSSION OF THIS QUESTION IS HERE: tom-working-alone-can-paint-a-room-in-6-hours-peter-and-126629.html
General Discussion
11 Aug 2011, 09:18
Kudos
Bookmarks
KunalPratap
T can work laone and finishes job in 6 hours, P & J can do the same independently in 3 and 2 hours each. P starts working and after 1 hour P joins, both of them work for another 1 hour. After that J joins them and thet finish the job together. What was freaction of job done by P????
1) 1/9
2) 1/6
3) 1/3
4) 7/18
5) 4/9
1) 1/9
2) 1/6
3) 1/3
4) 7/18
5) 4/9
Please correct your question. Who starts and who joins?
