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GMATinsight
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What about 726/627?
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462/264 , 143/34, 132/231,154/451 repitition??

There must be some easy way out.... :shock: :shock:
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462/264 , 143/34, 132/231,154/451 repitition??

There must be some easy way out.... :shock: :shock:

When a question talks about distinct digits it means that the digits in 1 number should be distinct and not that they need to unique thoroughout.

Example, 110 is not an acceptable case as 1 is repeated but 132 and 231 will be 2 good values. 'Distinct' does not apply (usually) apply to different numbers.
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it should be 10.
231
341
451
561
671
352
462
572
374
726
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Engr2012


Did by counting

132
143
154
165
176
231
243
264
275
341
352
374
451
462
473
517
671
761

GMATinsight, Total should be 18.

Did multiple mistakes due to mental calculations. Have updated options. There are 22 cases.

Thanks for notifying about my mistake.
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GMATinsight
Engr2012


Did by counting

132
143
154
165
176
231
243
264
275
341
352
374
451
462
473
517
671
761

GMATinsight, Total should be 18.

Did multiple mistakes due to mental calculations. Have updated options. There are 22 cases.

Thanks for notifying about my mistake.

I missed 4 cases :

The total cases are: 22. Your method is very useful.

132
143
154
165
176
231
253
264
275
341
352
374
451
462
473
517
561
572
627
671
715
726
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Engr2012
GMATinsight
Engr2012


Did by counting

132
143
154
165
176
231
243
264
275
341
352
374
451
462
473
517
671
761

GMATinsight, Total should be 18.

Did multiple mistakes due to mental calculations. Have updated options. There are 22 cases.

Thanks for notifying about my mistake.

I missed 4 cases :

The total cases are: 22. Your method is very useful.

132
143
154
165
176
231
253
264
275
341
352
374
451
462
473
517
561
572
627
671
715
726


CAN we Solve it in under 2 minutes on the test.!!!
I really doubt that.

P.S => i counted the cases and it took me 5 minutes upwards :)
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the best approach to go via rule if a number is divisible by 11 then take every 2nd digit (in our case the 1 in the middle) and subtract it from the sum of the rest digits, if the result is 0 or a multiple of 11 then we are settled
number x1x possible combination 7 and 5 (2 options as it could be 5 and 7)
number x2x possible combination 7 and 6 (2 options)
number x3x possible combination 1 and 2 (2 options)
number x4x possible combination 1 and 3 (2 options)
number x5x possible combination 3 and 2 also 4 and 1 (4 options)
number x6x possible combination 5 and 1 also 4 and 2 (4 options)
number x7x possible combination 5 and 2 also 4 and 3 also 6 and 1 (6 options)
Anyways, I found this question a bit time-consuming, that's the best approach to solve it, however, even using that it took me 3 mins or more, to double-check the responses as all answers are pretty much close to each other

I'm curious what are the odd to get that kind of question on GMAT? (instead of 11 that can be 7 or 13, non-standard divisibility patterns)
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This is brilliant question in the context of conceptual understanding of divisibility
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