Let's first analyze the information given in the problem:
Train A reaches the destination (300 km) when Train B still has 80 km left.
This means Train B has covered 220 km when Train A has covered 300 km.
Let vA and vB be the average speeds of Train A and Train B, respectively.
Let t be the time it took for Train A to travel 300 km.
From the information given:
𝑣𝐴=300
𝑡vA= t300
𝑣𝐵=220
𝑡vB=t220
To find
vA we needt, the time Train A took to travel 300 km.
Statement (1): During the first hour, Train B covered 40 kilometers less than Train A.
Let's denote the distance Train A covered in the first hour as
dA and the distance Train B covered in the first hour as dB.
From statement (1):
𝑑𝐵=𝑑𝐴−40
This gives us one equation, but it does not directly provide
t or vA
Statement (2): Train B's average speed for the first 110 kilometers was 110 kilometers per hour.
This means Train B traveled the first 110 kilometers in 1 hour:
𝑡𝐵1=110/110=1hour
Train B still needs to cover
220−110=110 kilometers. This second part of the journey is done in t−1 hours. The average speed of Train B for the entire 220 kilometers journey is:
vB=t220
Since the first part of the journey took 1 hour at 110 km/h, for the second part of the journey (110 km), the speed and time relation is:
𝑣𝐵2×(𝑡−1)=110
vB2 ×(t−1)=110
We also have:
220/𝑡 = 110/1+ 110(𝑡−1)
By solving this equation, we can find t and subsequently 𝑣𝐴=300𝑡
Combining both statements:
With statement (1), we have a relation between the speeds of Train A and Train B during the first hour, and with statement (2), we have detailed information on Train B's speed during the initial and subsequent phases of its journey. This combined information allows us to determine the exact average speeds of both trains and thus find
t. Hence C.