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09 Jul 2025, 08:00
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62% (01:34) correct
38%
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In a hot dog eating contest, two participants, Leo and Marco, competed for the same amount of time. During that time, Leo ate 36 hot dogs, and Marco ate 30 hot dogs. What was Marco’s average rate, in hot dogs per hour, during that time?
(1) Marco’s average rate was 6 hot dogs per hour less than Leo’s.
(2) In the first 20 minutes, Leo ate 12 hot dogs.
(1) Marco’s average rate was 6 hot dogs per hour less than Leo’s.
(2) In the first 20 minutes, Leo ate 12 hot dogs.
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09 Jul 2025, 08:30
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In a hot dog eating contest, two participants, Leo and Marco, competed for the same amount of time. During that time, Leo ate 36 hot dogs, and Marco ate 30 hot dogs. What was Marco’s average rate, in hot dogs per hour, during that time?
(1) Marco’s average rate was 6 hot dogs per hour less than Leo’s.
Assuming Marco’s average rate was x hot dogs per hour, Leo's rate would be x + 6 hot dogs per hour. Since they competed for the same amount of time, we can equate by time: 36/(x + 6) = 30/x. Solving this gives x = 30 hot dogs per hour. Sufficient.
(2) In the first 20 minutes, Leo ate 12 hot dogs.
This implies that Leo's average rate for the first 20 minutes was 36 hot dogs per hour. However, we cannot assume that Leo maintained the same rate while eating the remaining 36 - 12 = 24 hot dogs. He could have eaten those in 1 hour or in 10 hours, resulting in different total durations and, therefore, different rates for Marco. Not sufficient.
Answer: A.
GMAT Club Official Explanation:
In a hot dog eating contest, two participants, Leo and Marco, competed for the same amount of time. During that time, Leo ate 36 hot dogs, and Marco ate 30 hot dogs. What was Marco’s average rate, in hot dogs per hour, during that time?
(1) Marco’s average rate was 6 hot dogs per hour less than Leo’s.
Assuming Marco’s average rate was x hot dogs per hour, Leo's rate would be x + 6 hot dogs per hour. Since they competed for the same amount of time, we can equate by time: 36/(x + 6) = 30/x. Solving this gives x = 30 hot dogs per hour. Sufficient.
(2) In the first 20 minutes, Leo ate 12 hot dogs.
This implies that Leo's average rate for the first 20 minutes was 36 hot dogs per hour. However, we cannot assume that Leo maintained the same rate while eating the remaining 36 - 12 = 24 hot dogs. He could have eaten those in 1 hour or in 10 hours, resulting in different total durations and, therefore, different rates for Marco. Not sufficient.
Answer: A.
General Discussion
Emkicheru
Joined: 12 Sep 2023
Last visit: 12 Sep 2025
Posts: 119
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Location: Kenya
Schools: Anderson (UCLA) Sloan (MIT) Columbia '27
GMAT 1: 780 Q50 V48
GRE 1: Q167 V164
GPA: 3.7
Schools: Anderson (UCLA) Sloan (MIT) Columbia '27
GMAT 1: 780 Q50 V48
GRE 1: Q167 V164
Posts: 119
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09 Jul 2025, 08:31
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[quote="Bunuel"]In a hot dog eating contest, two participants, Leo and Marco, competed for the same amount of time. During that time, Leo ate 36 hot dogs, and Marco ate 30 hot dogs. What was Marco’s average rate, in hot dogs per hour, during that time?
(1) Marco’s average rate was 6 hot dogs per hour less than Leo’s.
(2) In the first 20 minutes, Leo ate 12 hot dogs.
[oly-gmatc2025][/oly-gmatc2025][/quote] total time is 1 hour since Leo ate 6 hots dogs more than Marco per hour,Leo ate 12 hots dogs in mins meaning 36 hot dogs per hence proves that Marco rate is 30 hot dogs per hour
(1) Marco’s average rate was 6 hot dogs per hour less than Leo’s.
(2) In the first 20 minutes, Leo ate 12 hot dogs.
[oly-gmatc2025][/oly-gmatc2025][/quote] total time is 1 hour since Leo ate 6 hots dogs more than Marco per hour,Leo ate 12 hots dogs in mins meaning 36 hot dogs per hence proves that Marco rate is 30 hot dogs per hour
