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15 Dec 2025, 10:13
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Two sets will be
first will be {2,3,5,7,11} ,
second set will be {7,11,13,17,19} ,
and to calclualte range = largest value - smallest value should be used ,
and according to the conditions mentioned only this combination is possible ,
so range for second set would be 19-7 = 12
so 12 is the answer
first will be {2,3,5,7,11} ,
second set will be {7,11,13,17,19} ,
and to calclualte range = largest value - smallest value should be used ,
and according to the conditions mentioned only this combination is possible ,
so range for second set would be 19-7 = 12
so 12 is the answer
15 Dec 2025, 10:17
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There are 2 sets A and B. We know that there is only 1 even prime number that is 2 and all other prime numbers are odd. Its given in the question that the range of smaller set is odd and we know that using number properties that odd - even = odd. therefore, the smalles number in the smaller set must be 2. So set A must be (2,3,5,7,11) (consecutive prime numbers) and Set B must be (7,11,13,17,19) since only 2 primes are common between the 2 sets and set B also has consecutive primes. Therefore, the range of Set B = (19-7=12) Option D
Bunuel
15 Dec 2025, 10:20
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If you subtract two odd numbers, the result will be even. To get an even difference, even and an odd number should be subtracted. The only even prime number is 2. Therefore, the smaller set starts with 2. It will have (2,3,5,7,11)
Since exactly two primes are common, 7 and 11 would be common in the next set. Going by consecutive prime nos, the other set will be (7,11,13,17,19). Therefore, range is 12.
Therefore, Option D
Since exactly two primes are common, 7 and 11 would be common in the next set. Going by consecutive prime nos, the other set will be (7,11,13,17,19). Therefore, range is 12.
Therefore, Option D
