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GMAT Club World Cup 2026 (Day 1): Along a straight coastal road, four

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Punt

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Bunuel

Along a straight coastal road, four stops, Harbor, Maple, Ridge, and Summit, appear in that order. Ridge is 3 times as far from Harbor as it is from Summit. Maple is 4 times as far from Ridge as it is from Harbor. What fraction of the distance from Harbor to Summit is the distance from Maple to Summit?

A. 3/20
B. 1/4
C. 2/5
D. 17/20
E. 20/17

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Let the stops lie on a number line in order
H<M<R<S
where H - harbour, M= Maple, R = Ridge, S = Summit

Condition 1
Ridge is 3 time a sfar from harbour as it is from summit.
Lety RS = x

Then, HR = 3x
Therefore, HS = HR + RS = 3x + x = 4X

Condition 2

Maple is 4 times as far from Ridge as it is from Harbor

Let HM = y
then, MR = 4y

Since HR = HM + MR
3x = y + 4y
Thus, y = 3x/5

So, HM = 3x/5

Then,
MS = HS - HM
= 4x - 3x/5 = 17x/5

Required fraction,
MS/HS = (17x/5)/4x = 17/20

Answer - D (17/20)

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i solved it using standard variables. H-M = 4. then M-R IS 16. hence H-R20 and r-s is 20/3

relation between h-s and m-s : 80/3 * k = 68/3

k = 17/20

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|-------|----------------|--------|
H------M---------------R--------S

Assume RS=100 so HR=300

HM=a MR=4a so HR=5a=300 a=60 & 4a=240

To find : xfraction f *HS=MS i.e f=MS/HS=340/400 =17/20 (D)

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Let distance from H~R Be 15a, R~S be 5a ( considering statement-1). similarly, H~M be 3b, and M~R be 12b(considering statement -2). if we observe distance from H~R in terms of a it is 15a, and in terms of B it is 15b ( 12b+3b). hence a=b. now the distance from M to S is 12b+5a = 17a ( since a=b). similarly, H~ S is 20a. so M~S/ H~S = 17/20.

Bunuel

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I believe the answer is D. 17/20.

The distance from H-R/R-S = 3/1

The distance from H-M/M-R = 1/4

Taking 20 as assumed number, H-R = 15, and R-S = 15

H-M/M-R = 3/12

So, M-S/H-S = 17/20

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06 Jul 2026, 08:43

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Answer: D) 17/20.

Is there another way to answer the Q without posting the answer? Will it register my answer if I click the answer choice?

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H - Harbour
M - Maple
R - Ridge
S - Summit

Attachments

IMG_20260706_211106423.jpg [ 798.25 KiB | Viewed 207 times ]

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The answer is 17/20 (d)

Explanation:
Lets consider HARBOR to be the starting point.
so H=0
and the rest of the stops are in the following order as mentioned in the question: 0<M<R<S.

To find the fraction of the distances between H to S and S to M, we need to find S and M as, H=0 (starting point).

The distance between R and H is 3 times the distance between R and S.
Lets denote this as follows,
R-H= 3(S-R)
H=0, so R= 3(S-R)
R= 3S-3R
R+3R=3S
4R=3S
S=4R/3

Second information given in the question is
R-M = 4 (M-H)
R-M = 4M
R=5M
M=1/5R

Now to get the fraction (S-H)/(S-M)
Lets put the value;
for S-H
(4R/3 - 0) = 4R/3

for S-M
4R/3 -1R/5
=(20R- 3R)/15
=17R/15

Putting these values in the fraction needed
we get 17/20.

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Let Harbor be H, Maple be M, Ridge be R and Summit be S.
We are given that:

<----------3y----------><---y--->
H--------M--------------R---------S
<---x----><----4x---->

That is: If the distance from Harbor to Maple = x, distance from Maple to Ridge = 4x
If the distance from Ridge to Summit = y, distance from Ridge to Harbor = 3y
And, 3y = x + 4x = 5x ----> (This can be inferred from above diagram)

We want to know what fraction of the distance from Harbor to Summit is the distance from Maple to Summit:
= $(4x + y) / 4y$
= $(4*3y/5) / 4y$ ------> (Substituting x = 3y/5)
= 17/20

IMO, the answer is D.

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We have to find the fraction of distances bw H and S / M to S. Lets take RS = x; HR = 3X. MH = Y; MR = 4Y. Solving, we get 5Y = 3X. HS/MS = 5Y + X / 4y + X; solve : 20/17.

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We will use the following alphabets for the names:
Harbour: H
Maple: M
Ridge: R
Summit: S

Question tells us:
They appear in the order: H - M - R - S

Distance b/w: R & S = 1/3 of distance between R & H
Distance b/w: M & R = 4* distance b/w M & H

Now let's work with this info:
Let, distance between M & H= A
Therefore, distance between M & R= 4A

Therefore, distance between H & R = 4A + A = 5A
And distance between R & S = (1/3)*5A

Now that we have all the values in terms of A, we look at the ratio we need to find which is:
(Distance b/w M & S) / (Distance b/w H&S)

Dist. b/w H&S= 5A + (1/3)5A = (20A)/3
Dist. b/w M&S= 4A + (1/3)5A = (17A/3)

Fraction:
=(17A/3)/(20A/3)
=17/20

Ans: D

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Bunuel

This question was provided by GMAT Club
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let H - Harbor , M - Maple, R- Ridge, S- summit
HR - distance from Harbor to Ridge,
RS - distance of summit from Ridge
so given, HR = 3 RS --- (1)
MR - distance of Ridge from Maple
HM - Distance of Maple from Harbor
Given, MR = 4 HM ---(2)
we know, since they are in a straight line in order,
HR = HM + MR ---(3)
from (1) and (2), (3)

HM + MR = 3 RS
HM +4 HM = 3RS
5HM = 3RS
RS = \frac{5}{3}HM ---(4)

required : MS : HS
since in a straight line :

HS = HM + MR + RS
from (2), (4)
HS = HM + 4HM + \frac{5}{3}HM
HS = \frac{20}{3}HM ----(5)

MS = MR + RS
from (2), (4)
MS = 4HM +\frac{5}{3}HM
MS = \frac{17}{3}HM ----(6)

from (5) and (6) ,
\frac{MS }{ HS } = \frac{17}{20}

D

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H____M____R____S
|-------3x------|---x--|
|---y---|--4y---|

HR = 3x
RS = x
HM = y
MR = 4y

HM+MR=HR
5y=3x
y=3x/5

HS = HR + RS = 4x
MS = MR+ RS = 4y + x = 17x/5 (sub y)

MS/HS = 17x/5/4x = 17/20

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H M R S
1. let distance between R to S = x
then R to H = 3x------------ 1

so H to S = 4x

2. now ,
let M to H = y
then M to R = 4y
H to R will be 5Y-------------2

from 1 and 2, we can say
3x=5y
or y=3x/5

now M to S = MR +RS
=4y+x

using the value of y,
= 4(3x/5) +x
=17x/5

now as per the asked in the question,
MS/HS= (17x/5)/4x= 17/20

answer is D

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H-R = 3y.
R-S = y.
H-M = x.
M-R = 4x.

Here, 5x = 3y.

We need:
y+4x / 4y.
Substituting for x, we get:
17/20.

Bunuel

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Let us denote each stop by their first letter alone, i.e. H/M/R/S.
They appear in order H->M->R->S.

We are given:
HR=3*RS
4*HM=MR

We also know:
HR=HM+MR, therefore
3*RS=5*HM, or
HM=RS*(3/5)

We need to find MS/HS.
MS=MR+RS=4*HM+RS=RS+RS*(3/5)*4=RS*(17/5)
HS=HR+RS=4*RS

Thus, MS/HS=(17/20) [Option D]

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Let the distance between R and S be x, so distance between H and R will be 3x.
Let the distance between H and M be y, so distance between M and R will be 4y.
so total distance will be 4x.
as per equation, 3x=5y. so y=3x/5
the required answer is (4y+x)/4x, equating this comes, 17/20/

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H—m-r-s is the sequence.
Hr =3x, rs =x
H M =y, mr=4y
We need ms/hs = x+4y/ 4 x
We know that 3x=5y( length of HR )
So by putting the value of y in the above equation we will get the of value of the required ratio, the value of y=3* x/5
We will get

Ms/hs =17/20

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Let Harbor → Ridge = 3 units and Ridge → Summit = 1 unit (because Ridge is 3 times as far from Harbor as from Summit).

Harbor → Ridge (3 units) is split into 1 part + 4 parts since Maple is 4 times as far from Ridge as from Harbor.

Harbor → Maple = 3/5

Maple → Ridge = 12/5

Maple → Summit = 12/5 + 1 = 17/5

Harbor → Summit = 3 + 1 = 4

Fraction:

17/5 over 4

equals 17 over 20

D: 17/20

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The places are arranged as below:

|<---------------d=(3a)----------------->|
Harbor_____d=(b)______Maple_______________Ridge________d=(a)______Summit
|<----d=(4b)----->|
First statement: Ridge is 3 times farther from Harbor as it is from Summit.
Let distance between Ridge and Summit be 'a'
Therefore dist. b/w Ridge and Harbor is 3a

Second statement: Maple is 4 times farther from Ridge as it is from Harbor,
Let distance between Harbor and Maple be 'b'
Therefor dist. b/w Maple and Ridge is 4b

Now we can see that 3a=4b+b
Thus, 3a=5b
Thus, 3a/5=b

We need to find dist (Maple,Summit) / dist (Harbor, Summit)

We know from the above diagram, that Dist(Maple,Summit) = Dist(Maple,Ridge)+Dist(Ridge,Summit)=4b+a
We also know, b=3a/5
Thus, 4b=12a/5

Thus 4b+a=(12a/5)+a=17a/5

Also, Dist (Harbor,Summit)=a+3a=4a

Thus the ratio then becomes, (17a/5)/4a=17/20

Answer is D