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06 Jul 2026, 10:12
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We know HR = 3*RS and MR =4 HM. HR : RS = 3:1 AND MR : HM = 4: 1 . We can assume entire distance from H to S be 60 then HR = 45 and RS= 15 and similarly when you take H-M-R then exclude R-S and consider the remaining region = 60-15 =45 now apportion MR = 36 and HM = 9 . Now we know HS =60 and we get MS = MR+RS = 36+15= 51 >>> Leads to MS /HS = 51/60= 17/20
Bunuel
06 Jul 2026, 10:14
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Let the distance from Harbour to Summit = S
Ridge is 3 times as far from Harbour as from Summit: R = 3(S-R).
Simplifying it, we get R = 3S/4.
Maple is 4 times as far from Ridge as from Harbour: R-M = 4M.
R = 5M
M = R/5 = 3S/20
Distance from M to S: S - 3S/20 = 17S /20
Distance from H to S is S
Required fraction: (17S/20) / S = 17/20
Answer - D (17/20)
Ridge is 3 times as far from Harbour as from Summit: R = 3(S-R).
Simplifying it, we get R = 3S/4.
Maple is 4 times as far from Ridge as from Harbour: R-M = 4M.
R = 5M
M = R/5 = 3S/20
Distance from M to S: S - 3S/20 = 17S /20
Distance from H to S is S
Required fraction: (17S/20) / S = 17/20
Answer - D (17/20)
06 Jul 2026, 10:19
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The question is as below:
H___M________R___D
‘s’ ‘4s’
|_____________|_____|
‘3d’ ‘d’
I have tried solving the question by assigning the distance a variable ‘d’ and ‘a’ and then tried to form equation with the help of above diagram:
Therefore 3d =s+4s
d = 5s/3
We are asked about MS/HS = ?
MS = 4s + d = 5s/3+ 4s =17s/3
HS = 3d+ d = 4d =4(5s)/3 =20s/3
MS/HS = 17s/ 20s =0.85 17/20
H___M________R___D
‘s’ ‘4s’
|_____________|_____|
‘3d’ ‘d’
I have tried solving the question by assigning the distance a variable ‘d’ and ‘a’ and then tried to form equation with the help of above diagram:
Therefore 3d =s+4s
d = 5s/3
We are asked about MS/HS = ?
MS = 4s + d = 5s/3+ 4s =17s/3
HS = 3d+ d = 4d =4(5s)/3 =20s/3
MS/HS = 17s/ 20s =0.85 17/20
