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GMAT Club World Cup 2026 (Day 1): Along a straight coastal road, four

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SRIVISHUDDHA22

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06 Jul 2026, 10:12

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We know HR = 3*RS and MR =4 HM. HR : RS = 3:1 AND MR : HM = 4: 1 . We can assume entire distance from H to S be 60 then HR = 45 and RS= 15 and similarly when you take H-M-R then exclude R-S and consider the remaining region = 60-15 =45 now apportion MR = 36 and HM = 9 . Now we know HS =60 and we get MS = MR+RS = 36+15= 51 >>> Leads to MS /HS = 51/60= 17/20

Bunuel

Along a straight coastal road, four stops, Harbor, Maple, Ridge, and Summit, appear in that order. Ridge is 3 times as far from Harbor as it is from Summit. Maple is 4 times as far from Ridge as it is from Harbor. What fraction of the distance from Harbor to Summit is the distance from Maple to Summit?

A. 3/20
B. 1/4
C. 2/5
D. 17/20
E. 20/17

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Let the distance from Harbour to Summit = S

Ridge is 3 times as far from Harbour as from Summit: R = 3(S-R).
Simplifying it, we get R = 3S/4.

Maple is 4 times as far from Ridge as from Harbour: R-M = 4M.
R = 5M
M = R/5 = 3S/20

Distance from M to S: S - 3S/20 = 17S /20

Distance from H to S is S

Required fraction: (17S/20) / S = 17/20

Answer - D (17/20)

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06 Jul 2026, 10:19

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The question is as below:
H___M________R___D
‘s’ ‘4s’
|_____________|_____|
‘3d’ ‘d’

I have tried solving the question by assigning the distance a variable ‘d’ and ‘a’ and then tried to form equation with the help of above diagram:

Therefore 3d =s+4s
d = 5s/3

We are asked about MS/HS = ?
MS = 4s + d = 5s/3+ 4s =17s/3

HS = 3d+ d = 4d =4(5s)/3 =20s/3

MS/HS = 17s/ 20s =0.85 17/20

MistyNova

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06 Jul 2026, 10:23

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Consider RH distance as 3x and RS distance as x, and let MR distance be 4y and MH distance be y.

HR=3x=y+4y
Equating we get y=3x/5

the ratio MS/HS = (4y+x)/(5y+x)

Substituting value of x, we get 17/20.

Bunuel

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_______3a________ ____a____
H_______M_______R_________S
____b___ ____4b__

MS/HS = ??

Let RS = a, so HR is 3a
Let HM = b, so MR is 4b

HR = 5b = 3a
b = 3/5 a

HS = 4a
MS = MR + RS = 4b + a = 4(3a/5) + a = 17a/5

HS/ MS = (17a/5)/4a = 17/20

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Lets suppose , the distance from H to S is 100.

If R is 3 times further from H than it is from S ,
HR= 3RS
but , HR+RS = 100
or, 4Rs =100
or, Rs = 25

so , the distance between R and S is 25.

If M is 4 times further from R than it is from H.
MR =4HM -----------( 1)

As ,
HM +MR = 75 ( R is at 100-25 =75 because RS is 25)
or, HM +4HM =75 [ FROM... (1) ]
or , HM= 15

M is at 15
R is at 75
S is at 100

so , distance from M to S is = 100-15 =85

fraction is = 85 /100 =17/20

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Taking First letter of the places to denote them: H,M,R,S

taking distance between R and S as X and Distance between H and M as Y

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Screenshot 2026-07-06 at 11.19.42 PM.png [ 1.26 MiB | Viewed 165 times ]

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Let the distance between Harbor and Summit be 80x.
Distance between Harbor and Ridge=60x
Distance between Ridge and Summit=20x

Now the distance between Harbor and Maple and the distance between Maple and Ridge is 1:4. Total Distance is 60x
Therefore distance between Harbor and Maple if 12x
Distance between Maple and Ridge is 48x.

Ratio of Maple to Summit/Harbor to Summit = (48x + 20x)/80x
=68x/80x = 17/20

Hence Answer Option D

Bunuel

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plot the harbour maple ridge and summit in a straight line
given RS=x
HR=4x
HM=y MR=4y
HS=x+3x=4x MS=4y+x
also
HR=y+4y=3x 5y=3x
solving we get MS/HS =17/20

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As shown in the attached figure,

Let HM = x,
So, MR = 4x and HR = 5x

Since HR = 3RS

RS = 5x/3

So, Distance from Harbor to Summit (HS) = HR + RS = 20x/3
and Distance from Maple to Summit (MS) = MR + RS = 18x/3

The requred fraction is MS/HS = 17/20

Correct answer: D

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Screenshot 2026-07-06 232244.png [ 203.14 KiB | Viewed 155 times ]

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Let the distance between HM be a, MR be b, RS be c.

We need to find MS/HS

Given that b = 4a
Also given that a + b = 3c
So, a + 4a = 3c
5a = 3c
c = 5a/3

HS = a + b + c = a + 4a + 5a/3
= 20a / 3

MS = b + c = 4a + 5a/3
= 17a/3

MS/HS = 17/20

Bunuel

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e can take the first sentence in terms of x and second sentence in terms of y. then we create a relation between x and y to get the total distance in one variable. now we calculate the distance of maple to summit in terms of that variable and take the ratio of Mape to summit/total distance

Bunuel

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Assume R-S = x
Then H-R = 3x

Assume H-M = y
Then M-R = 4y

Equating common sections H-R using both variables, we get:
3x = 5 y, so x = 5/3 y, hence R-S = 5/3 y

Now we have each segment in terms of y, so M-S is 4y + 5/3y, while total is 5y + 5/3y
Dividing both we get 17/20. ---- Answer (D)

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Stops are in Order - Harbor(H)>Maple(M)>Ridge(R)>Summit(S)
If distance between R-S is x then distance between R-H is 3x
Now, if distance between M-H is y then distance between M-R is 4y

But R-H = M-H + M-R
3x = 5y
x= 5y/3 which is the distance R-S

So total distance from H-S = y + 4y + 5y/3 = 20y/3
and distance between M-S = 4y + 5y/3 = 17y/3

So (17y/3)/(20y/3) = 17/20

y 4y
<-> <-->
H----M----R----S
<-------> <-->
3x x

Bunuel

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06 Jul 2026, 11:20

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Take the distance between Ridge and Harbour as 3x and that between Ridge and summit as x

Take the distance between Ridge and maple as 4y and that between Harbour and maple as Y

See the following illustration

3x x
-----------------|--------

H____ M ____ R ____S
y 4y

We need the fraction of (4y+x)/4x ....i

We can also see from the above that that 5y = 3x hence y = 3x/5 ... Plug this in place of y in i
(12*3x/5+x)/4x ----> Solve this you ll get 17/ 20 Hence answer is D

Bunuel

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Answer: E

Explanation:
Let the distance between Ridge and Summit be x, the distance between Harbor and Ridge be 3x, the distance between Harbor and Maple be y and the distance between Maple and Ridge be 4y.

To find the fraction:
Distance between M and S: Distance between H and S
= 4y+x/4x

As the distance between H and R:
5y=3x
y=3x/5

So the fraction is:
4y+x/4x
=(17x/5)/4x
=17/20

Bunuel

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06 Jul 2026, 11:30

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Let ridge to summit = x
harbor to ridge = 3x

Let harbor to maple =y
maple to ridge = 4y

hence 5y = 3x => y=(3/5)x
maple to summit / harbor to summit = (4y+x)/4x = (4(3x/5)+x)/4x=17/20
Answer D

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Let the total distance between the Harbor and Summit be 100m.
→ Starting from Harbor, Ridge is at 75m from it and 25m from Summit. maintaining the 3:1 ratio.
→ Similarly, Maple is at 15m from Ridge and 60m from Ridge, maintaining the 1:4 ratio.
→ Solving for the ratio of the Distance between Maple to summit to the total 100m.
(100-15)/100 = 85/100 = 17/20. D,

Bunuel

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Assume H to R is 300, R to S is 100, and then H to M is 60 and M to R is 240, i just assumed and got these numbers. Now once u follow this, 340/400 is the eqn, it comes down to 17/20 which is our answer.

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-----------------6-------------------
-----------------------------------------------------------
H--x---M--4x--R--2---S
let distances be :
H -> M : x
M -> R : 4x
H -> R : 6
R -> S : 2

We know therefore H to S is 8
To get M to S we divide it into 2 parts = M to R + R to S
Using ratios, M to R is 4x/5x * 6 = 24/5
thus, M to S => 24/5 + 2 = 34/5

HS * k = MS
8 * k = 34/5
k = 17/20

Therefore M to S is 17/20th fraction of H to S

Answer is D