Train A is traveling at 40 miles per hour and Train B is traveling on a parallel track in the same direction at 60 miles per hour. Currently, Train A is 15 miles ahead of Train B. How many minutes will it take Train B to catch up with Train A?Speed (Train A) = \(40 \frac{Miles}{Hour}\)
Speed (Train B) = \(60 \frac{Miles}{Hour}\)
Distance Between Train A and Train B
= 15 MilesAs both Train A and Train B are moving in the same direction, we have to subtract the higher speed from the lower speed to get the relative speed
= \(60 \frac{Miles}{Hour}\) - \(40 \frac{Miles}{Hour}\) = \(20 \frac{Miles}{Hour}\)
So, lets calculate the time required for Train B to catch-up with Train A:
\(Time = \frac{Distance}{Speed}\)
\(= \frac{15}{20}\)
= 0.75 HrsAs the time asked in the question is in minutes we will multiply it by 60
\(= 0.75 * 60\)
\(= 45 Min\)Hence, the Answer is A _________________
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