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Two ants start simultaneously from two ant holes towards each other. [#permalink]
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09 Sep 2009, 14:26
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54% (03:11) correct 46% (02:29) wrong based on 39 sessions
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Two ants start simultaneously from two ant holes towards each other. The first ant covered 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant traveled 800 feet to the meeting point. (A) 15 feet/h (B) 25 feet/h (C) 45 feet/h (D) 35 feet/h (E) 40 feet/h
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Re: Two ants start simultaneously from two ant holes towards each other. [#permalink]
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10 Sep 2009, 00:06
speed of ant1=(8/3)/100 of hole per hour speed of ant2=(7/120)/2,5=(7/3)/100 of hole per hour if ant1 goes 800 metres to meeting point then ant2 goes 700 metres. Total distance makes 1500 metres. speed of ant2=(7/3)/100 of hole per hour it makes (7/3)/100 * 1500= 35 metres per hour.
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Re: Two ants start simultaneously from two ant holes towards each other. [#permalink]
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10 Sep 2009, 01:49
maliyeci wrote: speed of ant1=(8/3)/100 of hole per hour speed of ant2=(7/120)/2,5=(7/3)/100 of hole per hour if ant1 goes 800 metres to meeting point then ant2 goes 700 metres. Total distance makes 1500 metres. speed of ant2=(7/3)/100 of hole per hour it makes (7/3)/100 * 1500= 35 metres per hour.
4)35 How did you get the statement in Red? s1=8d/300 and s2=7d/300 Now, how did you arrive at 800 and 700 as the distances?



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Re: Two ants start simultaneously from two ant holes towards each other. [#permalink]
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10 Sep 2009, 01:54
Economist wrote: maliyeci wrote: speed of ant1=(8/3)/100 of hole per hour speed of ant2=(7/120)/2,5=(7/3)/100 of hole per hour if ant1 goes 800 metres to meeting point then ant2 goes 700 metres. Total distance makes 1500 metres. speed of ant2=(7/3)/100 of hole per hour it makes (7/3)/100 * 1500= 35 metres per hour.
4)35 How did you get the statement in Red? s1=8d/300 and s2=7d/300 Now, how did you arrive at 800 and 700 as the distances? speed of ant1 = 8/300 of hole per hour speed of ant2 = 7/300 of hour per hour speed of ant1/speed of ant2=8/7 so in the time ant1 goes 800 metres, ant2 can go 700 metres



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Re: Two ants start simultaneously from two ant holes towards each other. [#permalink]
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10 Sep 2009, 02:22
Speed of ant1=> ant1 covers 8% of hole in 3 hours = 8/100/3=8/300 speed of ant2=> ant2 covers 7/120 in 2,5 hours = 7/120/2,5=7/300



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Re: Two ants start simultaneously from two ant holes towards each other. [#permalink]
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10 Sep 2009, 02:30
maliyeci wrote: Economist wrote: maliyeci wrote: speed of ant1=(8/3)/100 of hole per hour speed of ant2=(7/120)/2,5=(7/3)/100 of hole per hour if ant1 goes 800 metres to meeting point then ant2 goes 700 metres. Total distance makes 1500 metres. speed of ant2=(7/3)/100 of hole per hour it makes (7/3)/100 * 1500= 35 metres per hour.
4)35 How did you get the statement in Red? s1=8d/300 and s2=7d/300 Now, how did you arrive at 800 and 700 as the distances? speed of ant1 = 8/300 of hole per hour speed of ant2 = 7/300 of hour per hour speed of ant1/speed of ant2=8/7 so in the time ant1 goes 800 metres, ant2 can go 700 metres ahh i got it... so if we know speeds ( or ratio of speeds ) we can find ratio of distances keeping time as constant. s1/s2 = d1/d2 ( where t1=t2), hence, d1/d2 = 8/7...now d1 = 800, so d2 = 800*7/8 = 700. Nice concept! teşekkür ederim



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Re: Two ants start simultaneously from two ant holes towards each other. [#permalink]
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10 Sep 2009, 02:49
Economist wrote: teşekkür ederim Where did you learn our thanking words "Teşekkür ederim". I am very happy to see it. Have a nice day.



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Re: Two ants start simultaneously from two ant holes towards each other. [#permalink]
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10 Sep 2009, 03:10
maliyeci wrote: speed of ant1=(8/3)/100 of hole per hour speed of ant2=(7/120)/2,5=(7/3)/100 of hole per hour if ant1 goes 800 metres to meeting point then ant2 goes 700 metres. Total distance makes 1500 metres. speed of ant2=(7/3)/100 of hole per hour it makes (7/3)/100 * 1500= 35 metres per hour.
4)35 You are too good at this. Great going.
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Re: Two ants start simultaneously from two ant holes towards each other. [#permalink]
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10 Sep 2009, 07:01
speed of ant1 is 8/300 speed of ant2 is 7/300 so if ant1 covers 800 ant 2 will cover 700......speed of ant2 (7/3)/100 per hour hence (7/3)/100 * 1500= 35 metres per hour



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Two ants start simultaneously from two ant holes towards each other [#permalink]
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Updated on: 01 Mar 2017, 23:30
Two ants start simultaneously from two ant holes towards each other. The first ant covered 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant traveled 800 feet to the meeting point. (A) 15 feet/h (B) 25 feet/h (C) 45 feet/h (D) 35 feet/h (E) 40 feet/h
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Originally posted by saswata4s on 27 Feb 2017, 03:44.
Last edited by saswata4s on 01 Mar 2017, 23:30, edited 1 time in total.



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Re: Two ants start simultaneously from two ant holes towards each other [#permalink]
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27 Feb 2017, 17:31
saswata4s wrote: Two ants start simultaneously from two ant holes towards each other. The first ant covered 8% of the distance between the two ant holes in 3 hours, the second ant covered ____ of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant traveled 800 feet to the meeting point. (A) 15 feet/h (B) 25 feet/h (C) 45 feet/h (D) 35 feet/h (E) 40 feet/h Dear saswata4s, My friend, with all due respect, I believe something is missing from the test of the problems above. It's possible that if there were a math image, say, a fraction, and you copied and pasted, the math symbol did not paste into the plaintext of the GMAT Club problem box. You could retype what is missing in text, or use the math symbolism features. Actually, I found this question already posted here: https://gmatclub.com/forum/timespeedd ... 83745.htmlAlways search before you start a new thread for a question. Bunuel will have to merge the topics. Does all this make sense? Mike
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Re: Two ants start simultaneously from two ant holes towards each other [#permalink]
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01 Mar 2017, 23:32
Thanks mikemcgarry for pointing out. sorry for the inconvenience caused. Cheers.
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Re: Two ants start simultaneously from two ant holes towards each other. [#permalink]
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01 Mar 2017, 23:41
mikemcgarry wrote: saswata4s wrote: Two ants start simultaneously from two ant holes towards each other. The first ant covered 8% of the distance between the two ant holes in 3 hours, the second ant covered ____ of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant traveled 800 feet to the meeting point. (A) 15 feet/h (B) 25 feet/h (C) 45 feet/h (D) 35 feet/h (E) 40 feet/h Dear saswata4s, My friend, with all due respect, I believe something is missing from the test of the problems above. It's possible that if there were a math image, say, a fraction, and you copied and pasted, the math symbol did not paste into the plaintext of the GMAT Club problem box. You could retype what is missing in text, or use the math symbolism features. Actually, I found this question already posted here: https://gmatclub.com/forum/timespeedd ... 83745.htmlAlways search before you start a new thread for a question. Bunuel will have to merge the topics. Does all this make sense? Mike Topics merged. Thank you Mike.
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