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15 Feb 2004, 00:15
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Two dice each number from 1 to 6 are tossed n times
determine the least value of n for which the probability of obtaining at least one double "4" is greater than 1/2
determine the least value of n for which the probability of obtaining at least one double "4" is greater than 1/2
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15 Feb 2004, 00:27
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Computing probability for one dice is itself very complicated.
Two dice ! Hope we won't see these problems in real GMAT
I've used calculator to compute the answers and it is 24.
Method will fallow, if it is correct.
Two dice ! Hope we won't see these problems in real GMAT
I've used calculator to compute the answers and it is 24.
Method will fallow, if it is correct.
15 Feb 2004, 06:51
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If you throw pair of dice once P of not getting double 4 is 5^2/6^2
So if you throw N times then not getting even one double 4 = 5^2n/6^2n
So P of getting atleast one double 4 = (6^2n-5^2n)/6^2n
If we equate it to 1/2
we get
6^2n = 5^2n Only for N = 0 this equation is satisfied.
N cannot be determined.
I may be wrong here.
So if you throw N times then not getting even one double 4 = 5^2n/6^2n
So P of getting atleast one double 4 = (6^2n-5^2n)/6^2n
If we equate it to 1/2
we get
6^2n = 5^2n Only for N = 0 this equation is satisfied.
N cannot be determined.
I may be wrong here.
