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somya95

Two runners A and B start running towards each other in a straight line from points P and Q respectively. It is known that if they meet each other, or if they reach their starting positions they reverse their direction. Initially speed of A and B is in the ratio 1:2, but B halved his speed every time he reached point Q. What is the ratio of distance travelled by A to distance travelled by B till they meet for the 4th time?

A. 8:5
B. 9:4
C. 16:9
D. 19:16
E. 36:25


Here is another approach to solve this PS question

say, A starts from P
B starts from Q

Given, if they meet each other, or if they reach their starting positions they reverse their direction.

It essentially means that A and B travel towards each other, meet at M (say) and return to P and Q, respectively.
Post returning to Q, B halves his speed, but A maintains his original speed.
thus, covering a total distance equivalent to 2d


Now, P to M1 (meeting point 1) to P -->

A's speed : B's speed = 1:2
Distance (by A) = 2d/3; Distance (by B) = 4d/3..................Total distance covered = 2d..............(1)

then, P to M2 (meeting point 2) to P -->

A's speed : B's speed = 1:1 (ie, B halves his speed vis-a-vis previous speed)
Distance (by A) = 2d/2 = d; Distance (by B) = 2d/2 = d..................Total distance covered = 2d..............(2)

then, P to M3 (meeting point 3) to P -->

A's speed : B's speed = 1: 0.5 = 2:1 (ie, B halves his speed vis-a-vis previous speed)
Distance (by A) = 4d/3 ; Distance (by B) = 2d/3.............Total distance covered = 2d..............(3)

finally, P to M4 (meeting point 4) --> (Note : calculation only till 4th meeting point, ie, together distance = d, and NOT 2d)

A's speed : B's speed = 1: 0.25 = 4:1 (ie, B halves his speed vis-a-vis previous speed)
Distance (by A) = 4d/5 ; Distance (by B) = d/5.............Total distance covered = d..............(4)

Thus, we get

Distance (by A) : Distance (by B) = (2d/3 + d + 4d/3 + 4d/5) : (4d/3 + d + 2d/3 + d/5)
= (57d/15) : (48d/15)
= 57 : 48
= 19 : 16

(D) is the correct option

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