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# Two tanks T1 and T2 have a capacity of 1500 litres and 2000 litres res

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Retired Moderator
Joined: 22 Aug 2013
Posts: 1435
Location: India
Two tanks T1 and T2 have a capacity of 1500 litres and 2000 litres res  [#permalink]

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05 Aug 2018, 05:03
3
00:00

Difficulty:

45% (medium)

Question Stats:

67% (01:42) correct 33% (01:41) wrong based on 117 sessions

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Two tanks T1 and T2 have a capacity of 1500 litres and 2000 litres respectively. If a pipe P can fill empty tank T1 in X hours alone and empty tank T2 in Y hours alone while operating at same constant rate in both cases, what is the value of Y?

(1) Y/X = 4/3

(2) X = 6
Senior Manager
Joined: 29 Dec 2017
Posts: 383
Location: United States
Concentration: Marketing, Technology
GMAT 1: 630 Q44 V33
GMAT 2: 690 Q47 V37
GMAT 3: 710 Q50 V37
GPA: 3.25
WE: Marketing (Telecommunications)
Two tanks T1 and T2 have a capacity of 1500 litres and 2000 litres res  [#permalink]

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05 Aug 2018, 06:52
1
Let the speed of pipe P = p. We are told that the speed is constant, then

T1/x=T2/y, 1 500/x=2000/y, 3y=4x. So if we find value of X, we will know tha value of Y.

(1) Y/X = 4/3 - Not Suff because it gives us the same 3y=4x as we already know
(2) X = 6[/quote] - Suff, because we can now use the information in the given equation 3y=4x

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Joined: 18 Apr 2018
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Re: Two tanks T1 and T2 have a capacity of 1500 litres and 2000 litres res  [#permalink]

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17 Sep 2018, 01:26
Hero8888 wrote:
Let the speed of pipe P = p. We are told that the speed is constant, then

T1/x=T2/y, 1 500/x=2000/y, 3y=4x. So if we find value of X, we will know tha value of Y.

(1) Y/X = 4/3 - Not Suff because it gives us the same 3y=4x as we already know
(2) X = 6
- Suff, because we can now use the information in the given equation 3y=4x

Hello, I don't seem to be clear on your explanation. In stat 1 . We are given the ratio of both times and we're told that the pipe is operating at a constant rate in both tanks. Isnt it sufficient to find y?
Hero8888

Posted from my mobile device
Senior Manager
Joined: 29 Dec 2017
Posts: 383
Location: United States
Concentration: Marketing, Technology
GMAT 1: 630 Q44 V33
GMAT 2: 690 Q47 V37
GMAT 3: 710 Q50 V37
GPA: 3.25
WE: Marketing (Telecommunications)
Two tanks T1 and T2 have a capacity of 1500 litres and 2000 litres res  [#permalink]

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17 Sep 2018, 07:00
Kem12 wrote:
Hello, I don't seem to be clear on your explanation. In stat 1 . We are given the ratio of both times and we're told that the pipe is operating at a constant rate in both tanks. Isnt it sufficient to find y?
Hero8888

Posted from my mobile device

For any rate/speed problem on GMAT there is only one formula S=v*t (v=S/t or t=S/v), where S -distance/amount of work/number of production, 'v' - velocity/speed/work rate, 't' -time.

As 'v' - velocity is the same for both tanks (the same pipe), then $$v=S(x)/t(x)=S(y)/t(y) => 500/x=2000/y=>3y=4x=>y/x=4/3$$

And what does Statement 1 give you? Exactly the same information that you have been given in stem of the question. Clearly Statement 1 is insufficient.
Two tanks T1 and T2 have a capacity of 1500 litres and 2000 litres res   [#permalink] 17 Sep 2018, 07:00
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