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30 Jun 2015, 04:40
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
87% (01:28) correct
13%
(02:03)
wrong
based on 200
sessions
History
Date
Time
Result
Not Attempted Yet
Carina has 100 ounces of coffee divided into 5- and 10-ounce packages. If she has 2 more 5-ounce packages than 10-ounce packages, how many 10-ounce packages does she have?
A. 2
B. 4
C. 6
D. 8
E. 10
Kudos for a correct solution.
A. 2
B. 4
C. 6
D. 8
E. 10
Kudos for a correct solution.
30 Jun 2015, 04:51
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Carina has 100 ounces of coffee divided into 5- and 10-ounce packages. If she has 2 more 5-ounce packages than 10-ounce packages, how many 10-ounce packages does she have?
A. 2
B. 4
C. 6
D. 8
E. 10
Solution -
Lets say 5 and 10 ounce packages be x and y respectively.
Given that, 5x+10y=100 and x=y+2. What is the value of y.
Substituting the x in first equation, 5y+10+10y=100 ->y=6.
ANS C.
A. 2
B. 4
C. 6
D. 8
E. 10
Solution -
Lets say 5 and 10 ounce packages be x and y respectively.
Given that, 5x+10y=100 and x=y+2. What is the value of y.
Substituting the x in first equation, 5y+10+10y=100 ->y=6.
ANS C.
Updated on: 30 Jun 2015, 10:24
Originally posted by GMATinsight on 30 Jun 2015, 10:23.
Last edited by GMATinsight on 30 Jun 2015, 10:24, edited 1 time in total.
Last edited by GMATinsight on 30 Jun 2015, 10:24, edited 1 time in total.
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Bunuel
One 10-Ounce package = Two 5-Ounce package
Let, a packages of 10-Ounce package are available
i.e. a 10-Ounce package = 2a 5-Ounce package
Total Coffee in (2a) 5-Ounce package = (2a)*5
then the No . of 5-Ounce packages available = (a+2)
Total Coffee in (a+2) 5-Ounce package = (a+2)*5
Total Coffee = (a+2)*5 + (2a)*5 = 100
i.e. 15a + 10 = 100
i.e. a = 6
Answer: option C
