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Updated on: 09 Jul 2019, 04:06
Originally posted by Bunuel on 31 May 2017, 01:45.
Last edited by Sajjad1994 on 09 Jul 2019, 04:06, edited 1 time in total.
Last edited by Sajjad1994 on 09 Jul 2019, 04:06, edited 1 time in total.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
71% (01:23) correct
29%
(01:39)
wrong
based on 182
sessions
History
Date
Time
Result
Not Attempted Yet
If \(x^2 + y^2 = xy\), then \((x + y)^4 =\)
(A) \(xy\)
(B) \(x^2*y^2\)
(C) \(9x^2*y^2\)
(D) \((x^2 + y^2)^2\)
(E) \(x^4 + y^4\)
(A) \(xy\)
(B) \(x^2*y^2\)
(C) \(9x^2*y^2\)
(D) \((x^2 + y^2)^2\)
(E) \(x^4 + y^4\)
Source: Nova GMAT
Difficulty Level: 600
Difficulty Level: 600
31 May 2017, 04:06
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Given: x^2 + y^2 = xy
If we add 2xy to both sides, we get: x^2 + y^2 + 2xy = 3xy Or (x+y)^2 = 3xy
Now, (x+y)^4 = [(x+y)^2]^2 = (3xy)^2 = 9 * x^2 * y^2
Hence option C
If we add 2xy to both sides, we get: x^2 + y^2 + 2xy = 3xy Or (x+y)^2 = 3xy
Now, (x+y)^4 = [(x+y)^2]^2 = (3xy)^2 = 9 * x^2 * y^2
Hence option C
