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02 Jul 2017, 01:50
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C
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Difficulty:
15%
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Question Stats:
83% (01:58) correct
17%
(02:26)
wrong
based on 296
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The population of a certain country increases at the rate of 30,000 people every month. The population of the country in 2012 was 360 million. In which year would the population of the country be 378 million?
(A) 2060
(B) 2061
(C) 2062
(D) 2063
(E) 2064
(A) 2060
(B) 2061
(C) 2062
(D) 2063
(E) 2064
ydmuley
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Joined: 19 Mar 2014
Last visit: 01 Dec 2019
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Location: India
Concentration: Finance, Entrepreneurship
Schools: Haas '20 HBS '20 CBS '20 Wharton '20 Stanford '20 Kellogg '20
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02 Jul 2017, 02:35
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Bunuel
Population Increase Rate = 30,000 Per Month
Population in 2012 = 360 Million
Population in x year = 378 Million
378 Million - 360 Million = 18 Million
We want to calculate the year when the population increases by 18 Million
\(= \frac{18,000,000}{30,000} * \frac{1}{12}\) ====> 1/12 as we are converting per month to per year
\(= 50\) Years
Start Year \(= 2012\)
We will add 50 Years \(= 2012 + 50 = 2062\)
Hence, Answer is C
02 Jul 2017, 05:13
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Imo C
Rate of increase is 30000 per month , so per year it would be 12*30000=3,60,000 people
In 2012 population =360*10^6
In what year the population would be 378*10^6
378*10^6-360*10^6 =18*10^6
Now we have total increment dividing it by by the rate we will get the year
18*10^6/(3,60,000 )=50 years
so 2012+50=2062
hence answer C
Rate of increase is 30000 per month , so per year it would be 12*30000=3,60,000 people
In 2012 population =360*10^6
In what year the population would be 378*10^6
378*10^6-360*10^6 =18*10^6
Now we have total increment dividing it by by the rate we will get the year
18*10^6/(3,60,000 )=50 years
so 2012+50=2062
hence answer C
