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x^9 = 9^9^9
x=9^9
B

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Please see that (a^m)^n= a^m*n
Replacing x by 9^9 would mean (9^9)^9= 9^81

See that the number in question is much larger.
(9^9^8)^9= 9^9^8*9= 9^9^9

Answer D

Am unable to understand this explanation. Can someone explain it once again. Tia.
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Bunuel
If \(x^9 = 9^{9^9}\), what is the value of \(x\)?


A. \(9^8\)

B. \(9^9\)

C. \(9^{8^9}\)

D. \(9^{9^8}\)

E. \(9^{9^9}\)

Note that 9^9^9 is NOT the same as (9^9)^9 = 9^81. It is, instead, 9^(9^9), which is a much greater number than (9^9)^9.

Let’s take the 9th root of each side or rather, let’s raise each side to the power of 1/9:

(x^9)^(1/9) = [9^(9^9)]^(1/9)

x = 9^((9^9)*(1/9))

Since 1/9 = 9^(-1), we have:

x = 9^((9^9)*(9^(-1)))

x = 9^(9^(9 + (-1)))

x = 9^(9^8)

Answer: D
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Hello Can someone clarify one point for me please ?
Does :
(x^a)^b = x^(a*b) ?

x^a^b = x^(a*a*a*...*a) for example if b = 4 -> x^(a*a*a*a) ?

Thank you
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Hello Can someone clarify one point for me please ?
Does :
(x^a)^b = x^(a*b) ?

x^a^b = x^(a*a*a*...*a) for example if b = 4 -> x^(a*a*a*a) ?

Thank you

(x^a)^b = x^(a*b)

But x^a^b is not = (x^a)^b

It starts from the top ... For example x^a^b^c^d^e will start from solving d^e then c^d^e then b^c^d^e and so on.

2^3^4 = 2^81

Whereas (2^3)^4 = 8^4 which is completely different.

Hope this clarifies your doubt.
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Solution is attached

Posted from my mobile device
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IMG_20190806_133921932.jpg [ 2.19 MiB | Viewed 9698 times ]

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X^9 = 9^9^9

Using Log base 9:

9LogX = 9^9Log9 = 9^9

LogX = 9^9/9 = 9^8

X = 9^9^8

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x^9=9^(9)^(9)=(9^{(8+1)})^9 =>x^9=(9^(9)^8)^9 =>x=9^9^8­ 
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Here's an easier approach:

\((x)^9 = 9^{9^9}\)

Therefore x must be raised to some power. Let \(x = (a^b)\):
\((a^b)^9 = 9^{9^9}\)

Separate the exponents:
\(b*9 = 9^9\)
\(9^8*9^1 = 9^9\)

So:
\((a^{9^1})^{9^8} = 9^{9^9}\) --- 1
(OR)
\((a^{9^8})^{9^1} = 9^{9^9}\) --- 2

From the question, we know that we have to separate 9 from x (\((x)^9 = 9^{9^9}\)), so we go with eq 2­:

\((9^{9^8})^9 = 9^{9^9}\)­
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