Let's analyze the problem using the given statements and determine the sufficiency of each statement to find Train A's average speed.
Given Information:Train A and Train B depart simultaneously from Liverpool to London, 300 kilometers away.
When Train A reached London, Train B still had 80 kilometers left to cover.
Implications:Train A covered 300 kilometers while Train B covered 300−80=220 kilometers in the same time.
Let
TA be the time it took Train A to reach London, and
vA be Train A's average speed.
Let
vB be Train B's average speed.
From the problem statement, we have:
vA ⋅TA =300
vB ⋅TA =220
Statement (1):During the first hour, Train B covered 40 kilometers less than Train A.
Let
dA1 be the distance Train A covered in the first hour and
dB1 be the distance Train B covered in the first hour.
dB1=dA1−40
Since dA1=vA (Train A's speed) and dB1=vB (Train B's speed) for the first hour:
vB =vA −40
This equation alone doesn't provide enough information to find vA without additional data.
We need another relationship between vA and vB or their times to solve for vA
Statement (2):Train B's average speed for the first 110 kilometers was 110 kilometers per hour.
Train B covered 110 kilometers in 1 hour.
The rest of the journey for Train B was
220−110=110 kilometers.
We still need the total time for Train B's journey, which would help us relate Train A's journey time directly to their speeds. This statement doesn't directly give us the necessary relationship between
vA and the total travel time TA .
Combining Statements (1) and (2):Let's combine the information from both statements:
From (1):
vB =vA −40
From (2): Train B covered 110 kilometers in 1 hour at 110 km/h.
Now, we know Train B's speed is 110 km/h for the first hour and has 110 kilometers left for the rest of the journey:
After the first hour, Train B needs to cover the remaining 110 kilometers.
Let T2 be the time Train B takes to cover these 110 kilometers.
Thus, the total time for Train B is:
TB =1+T2
Using the total time relation for Train B:
vB.TA =220
Since vB=110:
110⋅(1+T2)=220
1+T2 =2
T2 =1
So, the total time TA for Train A is 2 hours because both trains traveled simultaneously:
vA⋅2=300
vA =150 km/h
Conclusion:Combining both statements, we are able to find the average speed of Train A.
Hence, the
answer is: C