Simply set the quadratic equation to zero and factor the roots out.

\({ x }^{ 2 }-4x=96\\ { x }^{ 2 }-4x-96=0\\ \left( x+8 \right) \left( x-12 \right) =0\\ x=-8,\quad x=12\)

For those people, like me, who struggle to find the roots, I suggest using one approach I took from

pacifist85.

Prime factorize the constant and see which number combinations that sum to 4 and multiply to 96.

\(96={ 2 }^{ 5 }\ast { 3 }^{ 1 }\)

You will eventually find the 8 and 12 roots.

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