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17 Jul 2017, 13:38
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
79% (01:55) correct
21%
(01:51)
wrong
based on 152
sessions
History
Date
Time
Result
Not Attempted Yet
What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder?
A. 1108
B. 1683
C. 2007
D. 3363
E. 3339
A. 1108
B. 1683
C. 2007
D. 3363
E. 3339
Updated on: 20 Feb 2020, 17:36
Originally posted by BrentGMATPrepNow on 17 Jul 2017, 14:15.
Last edited by BrentGMATPrepNow on 20 Feb 2020, 17:36, edited 1 time in total.
Last edited by BrentGMATPrepNow on 20 Feb 2020, 17:36, edited 1 time in total.
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GTExl
The biggest tip here is that the number is divisible by 9.
IMPORTANT: if a number is divisible by 9, the sum of its digits is divisible by 9.
Check the answer choices....
A. 1108 sum of digits = 10 - not divisible by 9 - ELIMINATE
B. 1683 sum of digits = 18 - divisible by 9 - KEEP
C. 2007 sum of digits = 9 - divisible by 9 - KEEP
D. 3363 sum of digits = 15 - not divisible by 9 - ELIMINATE
E. 3339 sum of digits = 18 - divisible by 9 - KEEP
We're left with B, C and E
Next important tip: the number, when divided by 5 leaves a remainder 3
Some numbers that work are: 3, 8, 13, 18, 23, 28, 33, ...
So, the number in question must have either 3 or 8 as its units digit.
Check the remaining answer choices....
B. 1683 KEEP
C. 2007 ELIMINATE
E. 3339 ELIMINATE
Answer: B
Cheers,
Brent
General Discussion
17 Jul 2017, 13:51
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What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder?
A. 1108
B. 1683
C. 2007
D. 3363
E. 3339
As per the question , number must be divisible by 9
So only B , C and E remains - out of these only B when divided by 5 leaves 3 as remainder
A. 1108
B. 1683
C. 2007
D. 3363
E. 3339
As per the question , number must be divisible by 9
So only B , C and E remains - out of these only B when divided by 5 leaves 3 as remainder
