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21 May 2013, 02:09
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What is the longest straight line that can be inscribed in a rectangle with a perimeter of 16 and sides of integer length?
A. 4 root 2
B. 6
C. 7
D. 5 root 2
E. 7 root 2
Grockit! please Explain
A. 4 root 2
B. 6
C. 7
D. 5 root 2
E. 7 root 2
Grockit! please Explain
21 May 2013, 02:18
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fozzzy
What is the longest straight line that can be inscribed in a rectangle with a perimeter of 16 and sides of integer length?
A. 4 root 2
B. 6
C. 7
D. 5 root 2
E. 7 root 2
Grockit! please Explain
A. 4 root 2
B. 6
C. 7
D. 5 root 2
E. 7 root 2
Grockit! please Explain
Basically we are asked to maximize the length of the diagonal in a rectangle with a perimeter of 16.
Say a and b are the lengths of the sides, then we have that 2a + 2b = 16 --> a + b = 8.
We need to maximize \(d=\sqrt{a^2+b^2}\). Since a and b are integers then \(d_{max}\) is obtained when a=1 and b=7 or vise-versa (by trial and error) --> \(d=\sqrt{a^2+b^2}=\sqrt{50}=5\sqrt{2}\).
Answer: D.
21 May 2013, 02:24
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Longest straight line that can be inscribed in a rectangle = the diagonal of that rectangle.
Longest diagonal can be obtained when one side of the rectangle has shortest possible length and the other side has the longest possible length when perimeter is constant.
In this case, as the sides are integers, shortest side can be 1 and longest side can be 7.
Then, diagonal of the rectangle = \(\sqrt{(1^2 + 7^2)} = \sqrt{50} = 5\sqrt{2}\)
Answer is D.
Longest diagonal can be obtained when one side of the rectangle has shortest possible length and the other side has the longest possible length when perimeter is constant.
In this case, as the sides are integers, shortest side can be 1 and longest side can be 7.
Then, diagonal of the rectangle = \(\sqrt{(1^2 + 7^2)} = \sqrt{50} = 5\sqrt{2}\)
Answer is D.
