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bluefox420
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area od rhombus = ( d1 * d2 ) /2
perimeter of rhombus = 4a
a = sqrt( sqr(d1/2) + sqr(d2/2) )
Answer should be D because we can find d1 and d2 given bothe the conditions.
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anandnk
area od rhombus = ( d1 * d2 ) /2
perimeter of rhombus = 4a
a = sqrt( sqr(d1/2) + sqr(d2/2) )
Answer should be D because we can find d1 and d2 given bothe the conditions.


could you pls put in the values and show how both statements, individually, are sufficient??

A) area = d1.d2/2
B) D1=48

how do we find "a" using these independently???
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anandnk
area od rhombus = ( d1 * d2 ) /2
perimeter of rhombus = 4a
a = sqrt( sqr(d1/2) + sqr(d2/2) )
Answer should be D because we can find d1 and d2 given bothe the conditions.

Agree... kudos! 8-)
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I think what anand meant was C. Since it said "since both are given....". Anand is this what you meant.

I think Ans is C.
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anandnk
area od rhombus = ( d1 * d2 ) /2
perimeter of rhombus = 4a
a = sqrt( sqr(d1/2) + sqr(d2/2) )
Answer should be D because we can find d1 and d2 given bothe the conditions.



how do you get D?

shouldnt it be C?



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