Paul,
Yeah. I agree now.
Here is how I thought about this problem (considering that it is whole numbers and not digits)
Now the probability = Number of ways in which 4 numbers are selected from the set of numbers that meet our criteria / Number of ways to select 4 numbers from all the possible numbers
For numerator, we have infinite possibilities from which to select 4 numbers (inf C 4)
But I think the key is to understand that there are 4 numbers with 1,3,7,9 in first 10 numbers. Similarly there are 40 numbers with 1,3,7,9 as unit digits in first 100 numbers. and so on...
Quote:
What I am not certain about is when Kpadma says: "Numbers that yield only 1,3,7 and 9 as unit digit
when two numbers are multiplied are number that have
1,3,7, and 9 in their unit digit."
I think what kpadma meant was if you take any four numbers with unit digit = 1,3,7, 9, the product of all the 4 numbers will always have 1,3,7,9 as unit digit. So that is OK. If any of the 4 numbers have a unit digit other that 1,3,7 or 9, the product will also have unit digit other than 1,3,7 or 9