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What is the value 201st term of a sequence if the first term

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What is the value 201st term of a sequence if the first term [#permalink]

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New post 20 Aug 2013, 12:54
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What is the value 201st term of a sequence if the first term of the sequence is 2 and each successive term is 4 more the term immediately preceding it?

(A) 798
(B) 800
(C) 802
(D) 804
(E) 806
[Reveal] Spoiler: OA

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Re: What is the value 201st term of a sequence if the first term [#permalink]

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New post 20 Aug 2013, 12:57
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Asifpirlo wrote:
What is the value 201st term of a sequence if the first term of the sequence is 2 and each successive term is 4 more the term immediately preceding it?
(A) 798
(B) 800
(C) 802
(D) 804
(E) 806


ITS AN AP
COMMON DIFFERENCE d = 4
first term = a
nth term = a+(n-1)d
201st term = 2+(200)4
= 802

hence C
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Re: What is the value 201st term of a sequence if the first term [#permalink]

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New post 23 Jul 2016, 22:49
Since first term is 2 : a1 = 2. Now the difference between 2 consecutive terms is 4 => an = an-1 + 4 .

The 201st term would be (201*4)-2 since the first term is 2.

The correct answer will be 802, Option C

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Re: What is the value 201st term of a sequence if the first term [#permalink]

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New post 29 Jul 2016, 15:11
Using the formula a[nthterm]=a+(n-1)d
a[201]=802=> Smash C
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Re: What is the value 201st term of a sequence if the first term [#permalink]

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New post 15 Sep 2017, 01:19
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Re: What is the value 201st term of a sequence if the first term [#permalink]

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New post 21 Sep 2017, 14:50
Asifpirlo wrote:
What is the value 201st term of a sequence if the first term of the sequence is 2 and each successive term is 4 more the term immediately preceding it?

(A) 798
(B) 800
(C) 802
(D) 804
(E) 806


The sequence described is an arithmetic sequence since each term (after the first) is a constant difference of 4 more than the previous term. To find the 201st term, we can use the following formula:

a_n = a_1 + (n - 1)d,

where a_1 is the first term, d is the common difference, n is the number of terms, and a_n is the nth term.

Here, a_1 = 2, d = 4, and n = 201; therefore, the 201st term is:

a_201 = 2 + (201 - 1)(4)

a_201 = 2 + 800

a_201 = 802

Answer: C
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Re: What is the value 201st term of a sequence if the first term   [#permalink] 21 Sep 2017, 14:50
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