Asifpirlo wrote:

What is the value 201st term of a sequence if the first term of the sequence is 2 and each successive term is 4 more the term immediately preceding it?

(A) 798

(B) 800

(C) 802

(D) 804

(E) 806

The sequence described is an arithmetic sequence since each term (after the first) is a constant difference of 4 more than the previous term. To find the 201st term, we can use the following formula:

a_n = a_1 + (n - 1)d,

where a_1 is the first term, d is the common difference, n is the number of terms, and a_n is the nth term.

Here, a_1 = 2, d = 4, and n = 201; therefore, the 201st term is:

a_201 = 2 + (201 - 1)(4)

a_201 = 2 + 800

a_201 = 802

Answer: C

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