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Bunuel
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Bunuel
What is the value of \(4x^2 + 5x – 2\) ?


(1) \(4x^2 + 4x + 1 = 0\)

(2) \(x(4x + 5) = 2\)


Are You Up For the Challenge: 700 Level Questions

From Statement - 1 : \(4x^2 + 4x + 1 = 0\)
It is of the form \(ax^2 + bx + c = 0\)
To find Roots, we use discriminant formula;
\(D = b^2 - 4ac\)
\(D = (4)^2 - 4(4)(1)\)
D = 16 - 16 = 0
This means roots are equal.

Hence we will have a unique value of 'x' and we can substitute the same in \(4x^2 + 5x – 2\) and find the equation's value.

Hence Sufficient

From Statement - 2 : \(x(4x + 5) = 2\)
Expanding equation :
\(4x^2 + 5x = 2\)
\(4x^2 + 5x - 2 = 0\)

equation's value = 0

Hence Sufficient

Therefore IMO answer is D
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Bunuel
What is the value of \(4x^2 + 5x – 2\) ?


(1) \(4x^2 + 4x + 1 = 0\)

(2) \(x(4x + 5) = 2\)


Are You Up For the Challenge: 700 Level Questions

Just a Note :

Both the statements are giving different answer values
From statement 1 we get x= -1/2 then \(4x^2 + 5x – 2\) = -3.5

Well as from statement 2 we get \(4x^2 + 5x – 2\) = 0

So both the statements are giving different values. This should not happen.
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