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25 Sep 2019, 00:59
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72% (01:18) correct
28%
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What is the value of a if \(\frac{a+1}{a+3} - \frac{a+2}{a+5} = 0\) ?
A. -2
B. -1
C. 0
D. 1
E. 2
A. -2
B. -1
C. 0
D. 1
E. 2
25 Sep 2019, 01:31
Kudos
Bookmarks
Really stuck here
we can rearrange
(a+1/a+3)-(a+2/a+4)=0 --> (a+1/a+3)=(a+2/a+4)
Cross multiply
(a+1)*(a+4)=(a+3)*(a+2)
I get 4=6
I just plugged the numbers and nothing satisfies the equation.
P.S. Seems I'm blind
we can rearrange
(a+1/a+3)-(a+2/a+4)=0 --> (a+1/a+3)=(a+2/a+4)
Cross multiply
(a+1)*(a+4)=(a+3)*(a+2)
I get 4=6
I just plugged the numbers and nothing satisfies the equation.
P.S. Seems I'm blind
25 Sep 2019, 02:59
Kudos
Bookmarks
Bunuel
What is the value of a if \(\frac{a+1}{a+3} - \frac{a+2}{a+4} = 0\) ?
A. -2
B. -1
C. 0
D. 1
E. 2
A. -2
B. -1
C. 0
D. 1
E. 2
Given, \(\frac{a+1}{a+3} - \frac{a+2}{a+4} = 0\)
--> \(\frac{(a+1)(a + 4) - (a+3)(a+2)}{{(a+3)(a+4)}} = 0\)
--> \(\frac{(a^2 + 5a + 4) - (a^2 + 5a + 6)}{{(a+3)(a+4)}} = 0\)
--> \(\frac{-2}{{(a+3)(a+4)}} = 0\)
It can never be 0, for any value of a!
Bunuel, Can you pls check once ?
