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31 Mar 2019, 00:34
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55% (01:42) correct
45%
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based on 51
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What is the value of B in the equation AX^2+BX+C=0,where A,B,C are integers
1. Product of the roots of the equation is 16
2. One root is 4 times the other
1. Product of the roots of the equation is 16
2. One root is 4 times the other
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31 Mar 2019, 00:57
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/let the roots be \(a_{1}\) and \(a_{2}\)
product of roots= \(a_{1} *a_{2} = \frac{c}{a}\)
and sum of roots = \(a_{1} +a_{2}=-\frac{b}{a}\)
Stmt A :product of roots= \(a_{1} *a_{2}= 16.=c/a\) not sufficient
Stmt B : sum of roots = \(a_{1} +a_{2} =-b/a\)
\(a_{1} =4a_{2}\) not suffcient
Combining a and B
\(a_{1} *4a_{2}\) = 16
thus \(a1= \pm2\)
hence since their are two values.
Value of b can be 4 or -4
not unique
Thus not sufficient
/hence answer E
product of roots= \(a_{1} *a_{2} = \frac{c}{a}\)
and sum of roots = \(a_{1} +a_{2}=-\frac{b}{a}\)
Stmt A :product of roots= \(a_{1} *a_{2}= 16.=c/a\) not sufficient
Stmt B : sum of roots = \(a_{1} +a_{2} =-b/a\)
\(a_{1} =4a_{2}\) not suffcient
Combining a and B
\(a_{1} *4a_{2}\) = 16
thus \(a1= \pm2\)
hence since their are two values.
Value of b can be 4 or -4
not unique
Thus not sufficient
/hence answer E
26 Jul 2022, 18:54
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