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# What is the value of d? (1) n^2 + an +b = (n + c)(n + d) (2) a - c=10

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What is the value of d? (1) n^2 + an +b = (n + c)(n + d) (2) a - c=10  [#permalink]

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17 Jan 2020, 01:35
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80% (01:57) correct 20% (01:13) wrong based on 5 sessions

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What is the value of d?

(1) $$n^2+an+b=(n+c)(n+d)$$
(2) $$a-c=10$$

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Re: What is the value of d? (1) n^2 + an +b = (n + c)(n + d) (2) a - c=10  [#permalink]

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17 Jan 2020, 06:11
Bunuel wrote:
What is the value of d?

(1) $$n^2+an+b=(n+c)(n+d)$$
(2) $$a-c=10$$

If n = 0, then using both statements, all we know is that b = cd and a = 10 + c, and d can be anything. So the answer is E.

I feel like that's not the intention behind the question; if instead we knew Statement 1 was true for every value of n, then by expanding the right side, we'd learn that c + d = a (since the coefficients in front of the 'n' terms would need to be equal on both sides), and since c + 10 = a from Statement 2, we'd know using both Statements that d = 10. But as the question is written, the answer is E.
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Re: What is the value of d? (1) n^2 + an +b = (n + c)(n + d) (2) a - c=10   [#permalink] 17 Jan 2020, 06:11