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Updated on: 25 Sep 2016, 06:52
Originally posted by Nevernevergiveup on 25 Sep 2016, 05:10.
Last edited by Nevernevergiveup on 25 Sep 2016, 06:52, edited 2 times in total.
Last edited by Nevernevergiveup on 25 Sep 2016, 06:52, edited 2 times in total.
Renamed the topic, edited the question and tags.
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E
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Difficulty:
55%
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Question Stats:
46% (01:08) correct
54%
(00:53)
wrong
based on 296
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Not Attempted Yet
What is the value of k?
(1) \(k^4 = \frac{1}{625}\)
(2) \(k^3 < k^2\)
(1) \(k^4 = \frac{1}{625}\)
(2) \(k^3 < k^2\)
25 Sep 2016, 05:49
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(1) \(K^4 = \frac{1}{625}\)
\(K^4\) =\(5^{-4}\)
==> k= \(5^{-1}\)= \(\frac{1}{5}\) or k =\(- \frac{1}{5}\) --Not Sufficient
(2) \(k^3 < K ^2\) -- Not sufficient
Lets combine (1) and (2).
\(k^3 < K ^2\) ==> \((- \frac{1}{5} )^3 < (- \frac{1}{5} )^2 ==> - \frac{1}{125} < \frac{1}{25}\) --True
\(k^3 < K ^2\) ==> \(( \frac{1}{5} )^3 < (- \frac{1}{5} )^2 ==> \frac{1}{125} < \frac{1}{25}\) --True
Ans E.
\(K^4\) =\(5^{-4}\)
==> k= \(5^{-1}\)= \(\frac{1}{5}\) or k =\(- \frac{1}{5}\) --Not Sufficient
(2) \(k^3 < K ^2\) -- Not sufficient
Lets combine (1) and (2).
\(k^3 < K ^2\) ==> \((- \frac{1}{5} )^3 < (- \frac{1}{5} )^2 ==> - \frac{1}{125} < \frac{1}{25}\) --True
\(k^3 < K ^2\) ==> \(( \frac{1}{5} )^3 < (- \frac{1}{5} )^2 ==> \frac{1}{125} < \frac{1}{25}\) --True
Ans E.
25 Sep 2016, 11:27
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Nevernevergiveup
What is the value of k?
(1) \(k^4 = \frac{1}{625}\)
(2) \(k^3 < k^2\)
(1) K=1/5 or -1/5 .....not sufficient(1) \(k^4 = \frac{1}{625}\)
(2) \(k^3 < k^2\)
(2)K^3-K^2<0
K^2(K-1)<0--------->K-1<0------->K<1.......not suff...
Combining again as K<1 (from 2)
K=1/5 or -1/5 .....not suff
Ans E
