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# What is the value of t^(-1)?

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Math Expert
Joined: 02 Sep 2009
Posts: 50007
What is the value of t^(-1)?  [#permalink]

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11 Nov 2017, 08:29
00:00

Difficulty:

5% (low)

Question Stats:

97% (00:52) correct 3% (01:06) wrong based on 80 sessions

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What is the value of $$t^{(-1)}$$?

(1) $$t^{(-2)} < 1$$

(2) $$t^{(-3)} = \frac{1}{27}$$

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Joined: 25 Feb 2013
Posts: 1216
Location: India
GPA: 3.82
Re: What is the value of t^(-1)?  [#permalink]

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11 Nov 2017, 09:11
Bunuel wrote:
What is the value of $$t^{(-1)}$$?

(1) $$t^{(-2)} < 1$$

(2) $$t^{(-3)} = \frac{1}{27}$$

Statement 1: $$t^{(-2)} < 1 => t^2>1$$. so we will not get any specific value of $$t$$ from this equation. Insufficient

Statement 2: $$t^{(-3)} = \frac{1}{27}$$, take the cube root ie. raise both sides to $$\frac{1}{3}$$ rd power

$$t^{(-1)} = \frac{1}{3}$$. Sufficient

Option B
Manager
Joined: 15 Aug 2016
Posts: 85
Re: What is the value of t^(-1)?  [#permalink]

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13 Nov 2017, 04:15
1/t=?

Statement 1-
t^2< 1
=> t must be between 0 and 1.Insuff

Statement 2-
1/t^3=1/27
=>t=3.
=> 1/t=1/3.Suff.

IMO:B
Intern
Joined: 22 Apr 2017
Posts: 28
Concentration: General Management, Operations
Re: What is the value of t^(-1)?  [#permalink]

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15 Nov 2017, 00:54
Bunuel wrote:
What is the value of $$t^{(-1)}$$?

(1) $$t^{(-2)} < 1$$

(2) $$t^{(-3)} = \frac{1}{27}$$

In value data sufficiency questions, your answer should be a specific value.

statement 1 produces a range while statement 2 will yield a specific value
Re: What is the value of t^(-1)? &nbs [#permalink] 15 Nov 2017, 00:54
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