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What is the value of x ? (1) (|x| - 1)(x - 2) = 0 (2) -1 ≤ x ≤ 1

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What is the value of x ? (1) (|x| - 1)(x - 2) = 0 (2) -1 ≤ x ≤ 1 [#permalink]

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New post 07 Nov 2017, 22:50
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E

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Question Stats:

71% (00:44) correct 29% (00:37) wrong based on 123 sessions

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Re: What is the value of x ? (1) (|x| - 1)(x - 2) = 0 (2) -1 ≤ x ≤ 1 [#permalink]

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New post 07 Nov 2017, 22:53
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1. x = -1, 1, 2
Not Sufficient.

2. x = -1, 1
Not Sufficient.

Both, x = -1, 1
Not Sufficient.

E.
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Re: What is the value of x ? (1) (|x| - 1)(x - 2) = 0 (2) -1 ≤ x ≤ 1 [#permalink]

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New post 21 Nov 2017, 04:32
Abhishiek wrote:
1. x = -1, 1, 2
Not Sufficient.

2. x = -1, 1
Not Sufficient.

Both, x = -1, 1
Not Sufficient.

E.


--------------------------

statement 2 can take values from -1,1 or any values between 1 & -1 since it isn't mentioned if x is an integer.
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Re: What is the value of x ? (1) (|x| - 1)(x - 2) = 0 (2) -1 ≤ x ≤ 1 [#permalink]

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New post 21 Nov 2017, 04:59
Bunuel wrote:
What is the value of x ?

(1) (|x| - 1)(x - 2) = 0

(2) -1 ≤ x ≤ 1


S1) x = -1,1,2
Insufficient

S2) -1 ≤ x ≤ 1
x can be any value between -1 & 1.
Insufficient.

S1+S2)
x = -1,1
Insufficient.

E is the answer.
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Re: What is the value of x ? (1) (|x| - 1)(x - 2) = 0 (2) -1 ≤ x ≤ 1 [#permalink]

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New post 21 Nov 2017, 22:34
Both together x should be 1 only because the statement 1 is satisfied with it and not with 0 or -1. So why not "C"?
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Re: What is the value of x ? (1) (|x| - 1)(x - 2) = 0 (2) -1 ≤ x ≤ 1 [#permalink]

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New post 21 Nov 2017, 22:38
Praharsha9 wrote:
Both together x should be 1 only because the statement 1 is satisfied with it and not with 0 or -1. So why not "C"?


What is the value of x ?

(1) (|x| - 1)(x - 2) = 0;

(|x| - 1) = 0 or (x - 2) = 0;

If (|x| - 1) = 0, then |x| = 1, so x = -1 or x = 1.
If (x - 2) = 0, then x = 2.

So, from this statement x could be -1, 1, or 2. Not sufficient.

(2) -1 ≤ x ≤ 1. Not sufficient.

(1)+(2) Two values of x satisfy both statements: x = -1 and x = 1. Not sufficient.

Answer: E.

Hope it's clear.
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Re: What is the value of x ? (1) (|x| - 1)(x - 2) = 0 (2) -1 ≤ x ≤ 1   [#permalink] 21 Nov 2017, 22:38
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