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# What is the value of x^2 - y^2? (1) x + y = 0 (2) x - y = 2

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Re: What is the value of x^2 - y^2? (1) x + y = 0 (2) x - y = 2 [#permalink]
x^2 - y^2 = (x-y)*(x+y)
(1) x+y = 0 => x^2 - y^2 = 0 regardless of the value of (x-y)
(2) x-y = 2. We don't know anything about x+y => insufficient.

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Re: What is the value of x^2 - y^2? (1) x + y = 0 (2) x - y = 2 [#permalink]