Last visit was: 12 Dec 2024, 08:50 It is currently 12 Dec 2024, 08:50
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 12 Dec 2024
Posts: 97,846
Own Kudos:
685,317
 [6]
Given Kudos: 88,255
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 97,846
Kudos: 685,317
 [6]
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 12 Dec 2024
Posts: 97,846
Own Kudos:
685,317
 [2]
Given Kudos: 88,255
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 97,846
Kudos: 685,317
 [2]
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
General Discussion
User avatar
msk0657
User avatar
Retired Moderator
Joined: 26 Nov 2012
Last visit: 14 Feb 2020
Posts: 472
Own Kudos:
Given Kudos: 46
Posts: 472
Kudos: 524
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
fredurst89
Joined: 04 Mar 2016
Last visit: 29 Mar 2017
Posts: 50
Own Kudos:
7
 [2]
Given Kudos: 6
Location: United Kingdom
GMAT 1: 710 Q49 V38
Products:
GMAT 1: 710 Q49 V38
Posts: 50
Kudos: 7
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think it is D. Both (1) and (2) are sufficient.
x^2 – y^2=(x+y)(x-y)

(1) abs(x)=abs(y) therefore either x=y or x=-y so either x+y or x-y are zero

(2) for those numbers to sum zero either the two of them are zero or one is the negative version of the other. Since x^2 cannot be a negative number, both x and y are zero.
User avatar
rohit8865
Joined: 05 Mar 2015
Last visit: 11 Dec 2024
Posts: 840
Own Kudos:
908
 [3]
Given Kudos: 45
Products:
Posts: 840
Kudos: 908
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
What is the value of x^2 – y^2?

(1) |x| = |y|
(2) x^2 + y^2 = 0
(1) sq. both side x^2=y^2
x^2 – y^2=0
suff....

(2) x^2 + y^2=0
two positive quantities add to 0 means both are 0

let write it as X^2=-y^2
since LHS is >=0 so as RHS
-y^2>=0---->y^2<=0
sq of a number is never negative so y must be 0
thus x=0
x^2-y^2=0
suff

Ans D
avatar
hsbinfy
Joined: 02 Mar 2012
Last visit: 13 Nov 2017
Posts: 196
Own Kudos:
Given Kudos: 4
Schools: Schulich '16
Schools: Schulich '16
Posts: 196
Kudos: 307
Kudos
Add Kudos
Bookmarks
Bookmark this Post
msk0657
Bunuel
What is the value of x^2 – y^2?

(1) |x| = |y|
(2) x^2 + y^2 = 0


Given to find the value of value of x^2 – y^2 ?

Stat 1: |x| = |y| => When there is mod on both LHS and RHS and being positive square both sides.

=> x^2 = y^2 => x^2 - y^2 = 0. Sufficient....

Stat 2 : x^2 + y^2 = 0 => x^2 = - ( y^2 ).

Sub this value in question stem we - ( y^2 ) - ( y^2 ) = - ( 2 * y^2 )...Insufficient..

IMO option A is correct answer...

OA please...will correct if I missed anything.

answer will be D

1st statement u have explained above

for 2nd
x^2+y^2=0

we know square of a positive number is always +ve.
as per 2nd statement ,
x^2+y^2=0

+ve + +ve =0

wait this should be positive(which is not possible here) or else if x and y both 0

so x and y are equal and their value=0

Suff


answer D
User avatar
DAllison2016
Joined: 07 Jul 2016
Last visit: 30 Sep 2016
Posts: 59
Own Kudos:
Given Kudos: 51
GPA: 4
Posts: 59
Kudos: 66
Kudos
Add Kudos
Bookmarks
Bookmark this Post
\(\text{What is the value of } x^2 – y^2?\)


\(\textbf{(1) } \vert x\vert = \vert y\vert\)

\(\sqrt{x^2} = \pm x = \vert x \vert\)

\(\vert x\vert = \vert y\vert \implies x^2 = y^2\)

\(x^2 - x^2 = 0\)

Sufficient. Answer = 0


\(\textbf{(2) } x^2 + y^2 = 0\)

The minimum value of squaring a number is 0.

Therefore, to obtain the answer of 0, \(x^2\) and \(y^2\) must both produce 0.
0 is the single single input which produces 0 as output. Therefore \(x = y = 0\)

As we know \(x\) and \(y\), we can obtain \(x^2 - y^2\)

Sufficient. Answer = 0

Note that (1) provides the answer, whereas (2) provides both the answer and the value of x and y.

(D) each statement alone is sufficient
Moderator:
Math Expert
97846 posts