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What is the value of x?
(1) x^2 – 4 = 20
(2) \(\frac{-2x+8\sqrt{\frac{6}{5}}}{0.8}\)=-x
(1) x^2 – 4 = 20
(2) \(\frac{-2x+8\sqrt{\frac{6}{5}}}{0.8}\)=-x
24 Feb 2017, 01:14
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(1) Because it is quadratic equation it has two possible values of X. This one alone is not sufficient.
(2) It this case X is not quadratic and has only one value so that (2) is alone sufficient. Hence right choice is Answer B.
(2) It this case X is not quadratic and has only one value so that (2) is alone sufficient. Hence right choice is Answer B.
