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1. Whats the smallest number greater than 2 that gives a remainder of 2 when divided by 15,21 and 37?
2. What is the greatest prime number that can divide 2^100 - 2^96?
3.There is a rectangle ABCD,such that One side BC = 8 and the other side AB=4.There is a point P on the side AD, which moves along AD.What is the probablity that the nime PB will not be greater than 5?
Since I dont have the answers,When mentioning the answer ,please try to explain.
Thanks.
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2^100 - 2^96 = 2^96*2^4 - 2^96
= 2^96 ( 2^4 - 1 )
= 2^96 ( 16 - 1 )
= 2^96 ( 15 )
Therefore, 2^96 has prime number 2 repeated 96 times. 15 has prime numbers 3 and 5. Since the question asks for the greatest prime number that divides them, 5 it is.
The other question is better explained with a diagram but as I said in a previous post, I suck at drawing those. Maybe I'll try later but that question is easier than the second one. It's about applying pythagore and knowing the hypothenuse.
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