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Quote:
When Matthew plays his favorite golf course, his probability of making a par or better on a par-3 hole is .3. If Matthew is playing his favorite golf course, and that course has exactly 4 par-3 holes, what is the probability that Matthew will make par or better on at least one of the par-3 holes?

A. 0.0081
B. 0.2401
C. 0.3000
D. 0.7599
E. 0.9919

1-P(NOT)=P(ATLEAST1)
P(NOT)=NNNN=(7/10)^4=2401/10,000
1-P(NOT)=10,000-2401/10,000=7599/10,000

Ans. (D)
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Probability of Matthew making par or better on a par-3 hole = 0.3.
Probality of not making a par or better =0.7
We are to determine the probability of Matthew making at least one par or better on a golf course that has exactly 4 par-3 holes.
Let P(none)= probability of Matthew not making par or better on any 4 par-3 holes and P(E)= probability of Matthew making par or better on at least one par-3 hole.
then P(E) = 1-P(none)
P(none)= 0.7^4= 0.2401
P(E)=1-0.2401 = 0.7599

The answer is, therefore, option D.
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When Matthew plays his favorite golf course, his probability of making a par or better on a par-3 hole is .3. If Matthew is playing his favorite golf course, and that course has exactly 4 par-3 holes, what is the probability that Matthew will make par or better on at least one of the par-3 holes?

P (at least one of the par-3 holes) = Total probability - none = 1 - 0.7 = 0.3

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