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Which of the following can never be a divisor of 4n - 2? Updated on: 22 Feb 2020, 08:21
Originally posted by CareerGeek on 21 Feb 2020, 20:06.
Last edited by CareerGeek on 22 Feb 2020, 08:21, edited 1 time in total.
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69% (01:42) correct 31% (01:37) wrong based on 131 sessions

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For any integer n, Which of the following can never be a divisor of 4n - 2?

A. 5
B. 6
C. 7
D. 8
E. 9

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D
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Which of the following can never be a divisor of 4n - 2? 22 Feb 2020, 08:00
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Dillesh4096
Which of the following can never be a divisor of 4n - 2?

A. 5
B. 6
C. 7
D. 8
E. 9

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Each of them could be a divisor of 4n - 2. I think the question should specify that n is an integer here.
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Which of the following can never be a divisor of 4n - 2? 22 Feb 2020, 08:20
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Bunuel

Each of them could be a divisor of 4n - 2. I think the question should specify that n is an integer here.
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Bunuel

Thank you. I missed it. Edited

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Which of the following can never be a divisor of 4n - 2? 22 Feb 2020, 08:43
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if n = 2: 4*2 - 2 =6 (divisible by 6)
if n = 3: 4*3 - 2 =10 (divisible by 5)
if n = 4: 4*4 - 2 = 14 (divisible by 7)
if n = 5: 4*5 - 2 = 18 (divisible by 9)

Hence, the correct answer is D.
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Which of the following can never be a divisor of 4n - 2? 22 Feb 2020, 10:33
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Dillesh4096
For any integer n, Which of the following can never be a divisor of 4n - 2?

A. 5
B. 6
C. 7
D. 8
E. 9

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Number properties

We can check answers by plugging in various n's. Logically, however, \(4n - 2\) is never a multiple of 4. This is because we subtracted 2 from a multiple of 4. Since \(4n - 2\) is never a multiple of 4, it cannot be a multiple of 8 either.

Ans: D
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Which of the following can never be a divisor of 4n - 2? 30 Nov 2024, 00:12
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2(2n-1)

It will be divisible by all the odd numbers including 6 as 6 is 2*3 in which 2 gets cancelled out and 3 will divide 2n-1.
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