Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1410:00 AM EST
-12:00 PM EST
Think a 100% GMAT Verbal score is out of your reach? Target Test Prep will make you think again! Our course uses techniques such as topical study and spaced repetition to maximize knowledge retention and make studying simple and fun.
Dec 1411:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.- Dec 15
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options.
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
76% (02:00) correct
24%
(02:19)
wrong
based on 46
sessions
History
Date
Time
Result
Not Attempted Yet
x and y are two digit positive integers. When x is divided by 9 and y is divided by 6, the quotients are the same and the remainders are the same. If x+y is 16 times the quotient, what is the ratio between the quotient and the remainder?
A. 1:1
B. 2:1
C. 3:2
D. 3:1
E. 4:1
source:self
A. 1:1
B. 2:1
C. 3:2
D. 3:1
E. 4:1
source:self
This Question is Locked Due to Poor Quality
Hi there,
The question you've reached has been archived due to not meeting our community quality standards. No more replies are possible here.
Looking for better-quality questions? Check out the 'Similar Questions' block below
for a list of similar but high-quality questions.
Want to join other relevant Problem Solving discussions? Visit our Problem Solving (PS) Forum
for the most recent and top-quality discussions.
Thank you for understanding, and happy exploring!
23 Aug 2017, 15:27
Kudos
Bookmarks
I'm not sure if this is the fastest way, but I just plugged in numbers and solved it pretty quickly
We are given
x = 9*q + r where q is the quotient and r is the remainder
y = 6*q + r
x + y = 16q
If q = 1, then 16q = 16 and x + y = 16
x = 9 + r and y = 6 + r
x + y = 15 + 2r
Since r is a remainder and must be an integer, then it is not possible for 15 + 2r to be 16.
If q = 2, then 16q = 32 and x + y = 32
x = 18 + r
y = 12 + r
x + y = 30 + 2r
30 + 2r = 32
Therefore r = 1
Therefore q = 2 and r = 1
We are given
x = 9*q + r where q is the quotient and r is the remainder
y = 6*q + r
x + y = 16q
If q = 1, then 16q = 16 and x + y = 16
x = 9 + r and y = 6 + r
x + y = 15 + 2r
Since r is a remainder and must be an integer, then it is not possible for 15 + 2r to be 16.
If q = 2, then 16q = 32 and x + y = 32
x = 18 + r
y = 12 + r
x + y = 30 + 2r
30 + 2r = 32
Therefore r = 1
Therefore q = 2 and r = 1
23 Aug 2017, 18:16
Kudos
Bookmarks
Given x=9q+r, y = 6q+r , where q & r are quotient and remainder respectively.
Also given x+y = 16q
It implies (9q+r)+ (6q+r) = 16q
15q+2r=16q
q=2r
q/r = 2/1
Also given x+y = 16q
It implies (9q+r)+ (6q+r) = 16q
15q+2r=16q
q=2r
q/r = 2/1
This Question is Locked Due to Poor Quality
Hi there,
The question you've reached has been archived due to not meeting our community quality standards. No more replies are possible here.
Looking for better-quality questions? Check out the 'Similar Questions' block below
for a list of similar but high-quality questions.
Want to join other relevant Problem Solving discussions? Visit our Problem Solving (PS) Forum
for the most recent and top-quality discussions.
Thank you for understanding, and happy exploring!
