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# (7^9 + 7^8)/8 =

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Math Expert
Joined: 02 Sep 2009
Posts: 64144

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Updated on: 08 Jul 2019, 00:16
00:00

Difficulty:

15% (low)

Question Stats:

100% (00:20) correct 0% (00:00) wrong based on 11 sessions

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$$\frac{7^9 + 7^8}{8} =$$

(A) 1/8
(B) 7/8
(C) 77/8
(D) 7^8
(E) 7^9

Source: Nova GMAT
Difficulty Level: 550

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Originally posted by Bunuel on 01 Jun 2017, 11:13.
Last edited by SajjadAhmad on 08 Jul 2019, 00:16, edited 1 time in total.
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Location: United States
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Re: (7^9 + 7^8)/8 =  [#permalink]

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01 Jun 2017, 11:33
1
(7^9+7^8)/8=(7^8)(7+1)/8=7^8

Is there a formatting issue? Should (D) 78 be (D) 7^8?
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Joined: 11 Sep 2015
Posts: 4875
GMAT 1: 770 Q49 V46
Re: (7^9 + 7^8)/8 =  [#permalink]

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01 Jun 2017, 11:49
1
Top Contributor
Bunuel wrote:
$$\frac{7^9 + 7^8}{8} =$$

(A) 1/8
(B) 7/8
(C) 77/8
(D) 78
(E) 79

$$\frac{7^9 + 7^8}{8} = \frac{7^8(7^1 + 1)}{8}$$

$$= \frac{7^8(7 + 1)}{8}$$

$$= \frac{7^8(8)}{8}$$

$$= 7^8$$

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Re: (7^9 + 7^8)/8 =  [#permalink]

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01 Jun 2017, 11:51
1
Bunuel wrote:
$$\frac{7^9 + 7^8}{8} =$$

(A) 1/8
(B) 7/8
(C) 77/8
(D) 78
(E) 79

I think there is a formatting problem. The answer should be 7^8.
Math Expert
Joined: 02 Sep 2009
Posts: 64144
Re: (7^9 + 7^8)/8 =  [#permalink]

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01 Jun 2017, 11:54
Mo2men wrote:
Bunuel wrote:
$$\frac{7^9 + 7^8}{8} =$$

(A) 1/8
(B) 7/8
(C) 77/8
(D) 78
(E) 79

I think there is a formatting problem. The answer should be 7^8.

Edited. Thank you.
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Re: (7^9 + 7^8)/8 =   [#permalink] 01 Jun 2017, 11:54