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Re: 7/(1/5) + 5/(1/7) = [#permalink]
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Bunuel wrote:
\(\frac{7}{\frac{1}{5}} + \frac{5}{\frac{1}{7}} =\)


A. 35/74

B. 74/35

C. 35

D. 70

E. 74


Key property: \(\frac{a}{\frac{b}{c}} = a \times \frac{c}{b}\)

So, \(\frac{7}{\frac{1}{5}} + \frac{5}{\frac{1}{7}} = (7 \times \frac{5}{1}) + (5 \times \frac{7}{1}) = (7 \times 5) + (5 \times 7) = 35 + 35 = 70 \)

Answer: D
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7/(1/5) + 5/(1/7) = [#permalink]
Bunuel wrote:
\(\frac{7}{\frac{1}{5}} + \frac{5}{\frac{1}{7}} =\)


A. 35/74

B. 74/35

C. 35

D. 70

E. 74

\(\frac{7}{\frac{1}{5}} + \frac{5}{\frac{1}{7}}\)

\(=\frac{7*5}{1} + \frac{5*7}{1}\)

\(= 35 + 35\)

\(= 70\), Answer must be (D)
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Re: 7/(1/5) + 5/(1/7) = [#permalink]
here if we simplify the equation we get
7/(1/5) = 7*5
and 5/(1/5) = 7*5

when we add both we get (7*5)+(7*5)
=35+35
= 70
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Re: 7/(1/5) + 5/(1/7) = [#permalink]
Bunuel wrote:
\(\frac{7}{\frac{1}{5}} + \frac{5}{\frac{1}{7}} =\)


A. 35/74

B. 74/35

C. 35

D. 70

E. 74

\(\frac{7}{\frac{1}{5}} + \frac{5}{\frac{1}{7}}\)

= \(7*5 + 5*7\)

= \(35 + 35\)

= \(70\), Answer must be (D)
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Re: 7/(1/5) + 5/(1/7) = [#permalink]
7/(1/5) + 5/(1/7)

solve as
7*5 + 5*7 = 35 + 35 = 70

Answer = D
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Re: 7/(1/5) + 5/(1/7) = [#permalink]
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Re: 7/(1/5) + 5/(1/7) = [#permalink]
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