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\(a^2*(b+3)*(c+9)=1\), where a, b and c are integers. Find the value of b*c?
1) b*c>16
2) b*c is square of positive number.
1) b*c>16
2) b*c is square of positive number.
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Updated on: 14 Sep 2019, 07:50
Originally posted by Archit3110 on 14 Sep 2019, 07:09.
Last edited by Archit3110 on 14 Sep 2019, 07:50, edited 1 time in total.
Last edited by Archit3110 on 14 Sep 2019, 07:50, edited 1 time in total.
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nick1816
\(a^2*(b+3)*(c+9)=1\), where a, b and c are integers. Find the value of b*c?
1) b*c>16
2) b*c is square of positive number.
1) b*c>16
2) b*c is square of positive number.
given expression can be simplified as
]\(a^2*(b+3)*(c+9)=1\)
a=1
b+3=1 ; b=-2 and c+9=1 ; c=-8
b+3=-1; b=-4 and c+9=-1 ; c=-10
so we get 1*(-2+3)*(-8+9)= 1
and 1*(-4+3)*(-10+9)=1
b*c = 16 and 40
#1
b*c>16
sufficient
#2
b*c is square of positive number
no unique value of b*c will be possible ; insufficient
IMO A
Updated on: 14 Sep 2019, 08:07
Originally posted by geezus24x7 on 14 Sep 2019, 07:59.
Last edited by geezus24x7 on 14 Sep 2019, 08:07, edited 1 time in total.
Last edited by geezus24x7 on 14 Sep 2019, 08:07, edited 1 time in total.
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Since a,b,c are integers
a^2 will always be positive and thus equal to 1
(b+3) and (c+9) can either be both positive or both negative. Therefore, b=-2 or -4 and c=-8 or -10
=> bc= 16 or 40
1.sufficient. bc =40
2. Sufficient. bc=16
Option?? (Third edit. I'm confused)
Posted from my mobile device
a^2 will always be positive and thus equal to 1
(b+3) and (c+9) can either be both positive or both negative. Therefore, b=-2 or -4 and c=-8 or -10
=> bc= 16 or 40
1.sufficient. bc =40
2. Sufficient. bc=16
Option?? (Third edit. I'm confused)
Posted from my mobile device
