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Hovkial
A certain company only accepts payments in its own special currency. The currency has the following denominations: one, ten and fifty. What is the number of different ways that a customer can pay the company if the customer's bill amounts to 107 in this currency?

(A) 15
(B) 16
(C) 17
(D) 18
(E) 19

107: 50, 10, 1

1 and 10: {7+100, 17+90, 27+80…97+10} = 10x
1 and 50: {7+100, 57+50} = 2x
1 only: {107} = 1x
1, 10 and 50: {7+50+50, 17+40+50, 27+30+50, 37+20+50, 47+10+50} = 5x

Total: 10+2+1+5=18

Ans (D)

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