Hovkial wrote:
A man intends to purchase atleastnine units each of pens, pencils and books during a sale. He purchases more pencils than pens and more books than pencils for a total of 32 items. What is the possible number of pencils purchased?
(A) 4
(B) 6
(C) 8
(D) 10
(E) 12
The question is of course missing the word ATLEAST. You cannot have all buying 9 units each and still having more books then pencils and so on..
Now, it is given that books > pencils > pens \(\geq{9}\)..
If we take pens as 10, pencils will be atleast 11 and books 12... Total =10+11+12=33....NOT possible, so pens have to be 9.This means books + pencils = 32-9=23.
let us check for possibilities.. pencils is 10, so books = 23-10=13..Possible
pencils is 11, so books = 23-11=12..Possible
pencils is 12, so books = 23-12=11.. NOT Possible, as books have to be GREATER than pencils..
Possible values of pencils -- 10 and 11
D
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