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# Absolute value (3 steps approach for complex problem) Pg 18

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Current Student
Joined: 27 Feb 2017
Posts: 34
Location: Singapore
Absolute value (3 steps approach for complex problem) Pg 18  [#permalink]

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17 Jan 2018, 03:05
Hi, could someone please advise how to decide where the negative sign should be placed for the 4 scenarios, whether it is before (x+3), (4-x), (8+x)?

Thanks,
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Math Expert
Joined: 02 Aug 2009
Posts: 8023
Re: Absolute value (3 steps approach for complex problem) Pg 18  [#permalink]

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17 Jan 2018, 07:58
gy88 wrote:
Hi, could someone please advise how to decide where the negative sign should be placed for the 4 scenarios, whether it is before (x+3), (4-x), (8+x)?

Thanks,

put a value of x in that in each scenario and see if each is negative..
si if x<-8..
x-1 .. -8-1=-9, so negative sign
in (3-x) ... 3-(-8) = 11, so positive sign and so on

hope it clears the query
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Re: Absolute value (3 steps approach for complex problem) Pg 18  [#permalink]

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22 Sep 2019, 00:19
Hi chetan2u

In the above attachment, shouldn’t the first condition represent as:

-(x-3)+(4-x)=-(8-x)

Since when x<-8, all three should be negative. So |4-x| should be -(4-x) and since -ve sign is already in the equation, -ve -ve should become positive

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Re: Absolute value (3 steps approach for complex problem) Pg 18  [#permalink]

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22 Sep 2019, 06:41
Sidmehra wrote:
Hi chetan2u

In the above attachment, shouldn’t the first condition represent as:

-(x-3)+(4-x)=-(8-x)

Since when x<-8, all three should be negative. So |4-x| should be -(4-x) and since -ve sign is already in the equation, -ve -ve should become positive

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No all three terms will NOT be negative..
4-x will not be negative when x<-8..

Say x=-10, so 4-x=4-(-10)=4+10=14. Thus 4-x>0
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Re: Absolute value (3 steps approach for complex problem) Pg 18   [#permalink] 22 Sep 2019, 06:41
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