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Re: At a certain automobile dealership that sells only Tajimas and Franks, [#permalink]
Kauner wrote:
At a certain automobile dealership that sells only Tajimas and Franks, the number of nonhybrid Tajimas is 35 less than 3 times the number of hybrid Tajimas. 205 total Tajimas are currently owned by the dealership. If the ratio of hybrid Tajimas to nonhybrid Franks is 5:4 and there are 280 total automobiles owned by the dealership, how many hybrid Franks are there?

a 20
b 27
c 48
d 60
e 87



took me >120 seconds to solve this, is there an easier way ?


Franks = 280 - 205 = 75
Let hybrid Tajimas = X , So nonhybrid Tajimas = 3X-35
Now ,
X + ( 3X -35 ) = 205
=> 4X = 240
=> X = 60

So , from 5 : 4
5X = 60
X = 12

Nonhybrid frank = 4*12 = 48
Hybrid frank = 75 - 48 = 27

Answer : B
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Re: At a certain automobile dealership that sells only Tajimas and Franks, [#permalink]
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Kauner wrote:
At a certain automobile dealership that sells only Tajimas and Franks, the number of nonhybrid Tajimas is 35 less than 3 times the number of hybrid Tajimas. 205 total Tajimas are currently owned by the dealership. If the ratio of hybrid Tajimas to nonhybrid Franks is 5:4 and there are 280 total automobiles owned by the dealership, how many hybrid Franks are there?

a 20
b 27
c 48
d 60
e 87


We can let n = the number of nonhybrid Tajimas and h = the number of hybrid Tajimas. Thus:

n = 3h - 35

Since a total of 205 Tajimas are currently owned by the dealership:

n + h = 205

3h - 35 + h = 205

4h = 240

h = 60

Since h = 60, n = 145.

We are also given that the ratio of hybrid Tajimas to nonhybrid Franks is 5:4 = 5x : 4x.

Since the number of hybrid Tajimas is 60, we can say that 5x = 60, or x = 12. Thus, there are 4(12) = 48 nonhybrid Franks.

Since there are 280 cars at the dealership, we can create the following equation in which f = the number of hybrid Franks.

280 = 60 + 145 + 48 + f

280 = 253 + f

27 = f

Answer: B
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Re: At a certain automobile dealership that sells only Tajimas and Franks, [#permalink]
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