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# At the same time Fredrick started walking toward Bernard's house, a

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Re: At the same time Fredrick started walking toward Bernard's house, a [#permalink]
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Bunuel wrote:
At the same time Fredrick started walking toward Bernard's house, a distance of 70 blocks, Barnard left his house along the same route to meet him. If Fredrick was traveling at 6 blocks every ten minutes and Bernard was traveling at 8 blocks every ten minutes, how long did it take them to meet?

A. 5 minutes
B. 10 minutes
C. 35 minutes
D. 50 minutes
E. 70 minutes

This is a converging rate problem in which we can use the following formula:

distance of Fredrick + distance of Bernard = total distance

Since Fredrick walks 6 blocks every 10 minutes, his rate is 6/10 = 3/5 blocks per minute. Since Bernard walks 8 blocks every 10 minutes, his rate is 8/10 = 4/5 blocks per minute. Since distance = rate x time, and if we let t = the time they travel before they meet, Frederick’s distance is (3/5)t and Bernard’s distance is (4/5)t. Thus:

(3/5)t + (4/5)t = 70

7t/5 = 70

7t = 350

t = 50

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Re: At the same time Fredrick started walking toward Bernard's house, a [#permalink]
Bunuel wrote:
At the same time Fredrick started walking toward Bernard's house, a distance of 70 blocks, Barnard left his house along the same route to meet him. If Fredrick was traveling at 6 blocks every ten minutes and Bernard was traveling at 8 blocks every ten minutes, how long did it take them to meet?

A. 5 minutes
B. 10 minutes
C. 35 minutes
D. 50 minutes
E. 70 minutes

Option:D
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