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# At Tyler High School, there are twice as many girls than boys on the

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Re: At Tyler High School, there are twice as many girls than boys on the [#permalink]
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Bunuel wrote:
At Tyler High School, there are twice as many girls than boys on the yearbook staff. At one staff meeting, the percentage of girls attending was twice the percentage of boys. What percent of those attending were boys?

A) 20

B) 25

C) 30

D) 33

E) 50

We can let the number of girls = 20 and the number of boys = 10. We can let the percentage of girls attending = 100 and the percentage of boys = 50.

Thus, there were 20 girls and 5 boys, so the percentage of boys was 5/25 = 1/5 = 20%.

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Re: At Tyler High School, there are twice as many girls than boys on the [#permalink]
Bunuel wrote:
At Tyler High School, there are twice as many girls than boys on the yearbook staff. At one staff meeting, the percentage of girls attending was twice the percentage of boys. What percent of those attending were boys?

A) 20

B) 25

C) 30

D) 33

E) 50

There are TWO parts..

(I) Strength

there are twice as many girls than as boys on the yearbook staff --- so G=2B

(II) Meeting

the percentage of girls attending was twice the percentage of boys. What percent of those attending were boys
Now let the % of boys attending be x or 10%, then the % of girls attending be 2x or 20%.
Number of girls attending = 2x*G=2x*2B=4x*B
Number of girls attending =x*B

What percent of those attending were boys?
Total attending = 4x*B+x*B=5x*B
Boys = x*B

percent = $$\frac{x*B}{5x*B}*100=\frac{1}{5}*100=20%$$
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At Tyler High School, there are twice as many girls than boys on the [#permalink]
Bunuel wrote:
At Tyler High School, there are twice as many girls than boys on the yearbook staff. At one staff meeting, the percentage of girls attending was twice the percentage of boys. What percent of those attending were boys?

A) 20
B) 25
C) 30
D) 33
E) 50

Let number of girls = G and number of boys = B at THS.
Here G = 2B
Let number of girls present in meeting = g and number of boys = b
Now, $$\frac{g}{G} = 2\frac{b}{B}$$

Taking numbers as G = 100 and B = 50 and assuming $$\frac{g}{G} * 100 = 40%$$, so $$\frac{b}{B} * 100 = 20%$$
Hence g = 40 and b = 10
Thus, $$\frac{b}{b + g} * 100 = 20%$$